can someone help me with matrices?

- anonymous

can someone help me with matrices?

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- schrodinger

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- anonymous

Hey Rld!

- anonymous

Like how do I find and inverse of a matrix using the product of elementary matrices

- anonymous

Hey mhp :D

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## More answers

- anonymous

I need to find the inverse of a matrix using elementary matrices What doe sthat mean?

- 2bornot2b

The inverse of a given matrix is a matrix, which when multiplied with the given matrix gives identity.

- amistre64

there is something called a cofactor matrix, that is tranposed and then divided out by the determinate of the original

- anonymous

no I need to use the product of the elemntary matrices idk

- amistre64

youll have to define what that is

- anonymous

LOL It tells me to find the inverse of a amtrix using elementary matrices

- anonymous

What do u think that means?

- anonymous

if i copy from a book
if AB=BA = I

- anonymous

theres more to it though

- amistre64

\begin{pmatrix}a&b&c\\e&f&g\\h&j&k\end{pmatrix}
\begin{pmatrix}+|\begin{array}c f&g\\j&k\end{array}|\end{pmatrix}
cant tell if that formats

- anonymous

can u guys plz help me with my question?

- amistre64

\[\begin{pmatrix}+|\begin{array}c f&g\\j&k\end{array}|&
-|\begin{array}c e&g\\h&k\end{array}|&
+|\begin{array}c e&f\\h&j\end{array}|\\
-|\begin{array}c b&c\\j&k\end{array}|&
+|\begin{array}c a&c\\h&k\end{array}|&
-|\begin{array}c a&b\\h&j\end{array}|\\
+|\begin{array}c b&c\\f&g\end{array}|&
-|\begin{array}c a&c\\e&g\end{array}|&
+|\begin{array}c a&b\\e&f\end{array}|\\
\end{pmatrix}^T\frac{1}{det}=inverse\]
those sub matrixes are the determinants values of those things

- amistre64

dunno if its what its calling for tho :/

- Zarkon

those are not elementary matrices

- anonymous

noooo they want something simple but obviously they didnt show an example and like i cant figure it out

- Zarkon

here is an example ... http://stattrek.com/matrix-algebra/how-to-find-inverse.aspx

- amistre64

bummer, i memorized it for naught lol

- anonymous

Thanks amistre lol

- amistre64

isnt that the gauss jordon?

- anonymous

Ya s/t like that LOL

- anonymous

Zarkon that is what I needed

- anonymous

Thanks Guys :DDDD

- anonymous

ty zarkon

- anonymous

i didnt have to type the rst of the stuff

- anonymous

lol didnt forget abt yesterday mth. Do u still need help?

- anonymous

im just getting it from the book :P

- anonymous

hmmm
correct me if i am wrong
on a coordinate plane the sine and cosine waves
to find their angle measurement would it just be the same same way
as finding them in a regular circle
then to find their line measure
how to do that
if it was just plot right in the middle of a coordinate plane

- anonymous

|dw:1327259052486:dw|
This is how u wld draw it

- anonymous

this is a sin curve

- anonymous

now there is another thing of evaluating triangles like the degrees and measurements
sohcahtoa

- anonymous

|dw:1327259201697:dw|
have u ever seen this?

- anonymous

|dw:1327259258899:dw|

- anonymous

Do u know what I am talking abt?

- anonymous

umm sohcahtoa i know

- anonymous

ohhh so u r not referring to that

- anonymous

sin curve cosine curve i know

- anonymous

wait

- anonymous

ok i guess i am XD

- anonymous

i just have not seen the second to last drawing

- anonymous

oh it is abt cast

- anonymous

|dw:1327259558434:dw|
these are the quadrants

- anonymous

In the first quadrant A=ALL is positive
In the second quadrant S = Sin only sin is positive while verything else is negative
In the third quadrant T= Tan only tan is positive
In the fourth quadrant C=only cos is positive

- anonymous

This is referring to triangles in the coordinate plane. It all depends in which quadrant the triangle is in

- anonymous

ooo

- anonymous

I dont think that was clear

- anonymous

LOL I need to review my trig I learnt it so long ago

- anonymous

K I gotta go :(((((
i am behind in my work

- anonymous

Too much work and little time
I hope my prof will give me an extension. She aleady gave me one last week lOL

- anonymous

all i know about the coordinate plane is that
quadrant 1 = y is +, x is +
quad 2 = y is +, x is-
quad 3 = y is - , x is -
quad 4 = y is - , x is +

- anonymous

lol

- anonymous

you very lucky

- anonymous

bb

- anonymous

ty

- anonymous

LOL I didnt help u much

- anonymous

help is help
i appreciate all i get

- anonymous

I wish i wld be able to help but i am so busy. i tutor and then I took on this subbing job

- anonymous

I AM SO BUSY I HATE IT. I WISH I HAD TIME FOR MYSELF

- anonymous

:P

- anonymous

U became so serious suddenly lol

- anonymous

lol

- anonymous

Its like u r a diff person

- anonymous

i like to make fun of life

- anonymous

never serious
but it gets to the point :)

- anonymous

lol

- anonymous

besides where did you see me do such a thing ?

- anonymous

What be serious ??????? right now lol

- anonymous

hehe

- anonymous

no can do
sawy

- anonymous

huh?

- anonymous

i dont know
being serious is something i can do easily i dont know why

- anonymous

LOL hard to believe gonna get back to work

- anonymous

go go go

- anonymous

LOL I dont know how to leave os

- anonymous

i dont be the one to cause apocalyse

- anonymous

huh? what doe sthat mean?

- anonymous

apocalypse is kinda --end of the world

- anonymous

mth r u someone else?

- anonymous

im lazy to make another account and have a bad memory of pw

- anonymous

LOL the comp remembers it for u

- anonymous

I have a feeling that u r hero

- anonymous

LOL no response

- anonymous

i hate flipping pages to find the pw

- anonymous

then there is email account

- anonymous

then theres another account

- anonymous

this account

- anonymous

and that

- anonymous

ugg

- anonymous

It simpler than u think

- anonymous

U amy be hero lol

- anonymous

of course its easy
but
im lazy remember

- anonymous

R u hero?

- anonymous

nope

- anonymous

LOL u r acting like him lol

- anonymous

how does he act?

- anonymous

LOL not telling u

- anonymous

well hes typing now

- anonymous

so i dont see how i can be him/her

- anonymous

LOL OK

- anonymous

cutter10
question

- anonymous

^^

- anonymous

lol no

- anonymous

lol humor is fun

- anonymous

LOL

- anonymous

i have leeched an hour of you work time
not that i want you to leave
but
i really want you to get your work done

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