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anonymous
 4 years ago
\[F(x)=f(g(x)), \space f'(x)=\frac{x^2+1}{x5}, \space g(x)=\sqrt{x}.\]
Find F(x).
anonymous
 4 years ago
\[F(x)=f(g(x)), \space f'(x)=\frac{x^2+1}{x5}, \space g(x)=\sqrt{x}.\] Find F(x).

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0so we need to find f so we need to integrate f' \[\int\limits_{}^{}\frac{x^2+1}{x5} dx\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0x+5  x5 x^2+0x+! (x^25x)  5x+1 (5x25)  26 so we have \[\int\limits_{}^{}(x+5+\frac{26}{x5}) dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F =\rightarrow \sum_{^{_{_{\sqrt[\sqrt[?]{?}]{?}}^{?}}}}^{?}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{x^2}{2}+5x+26 \ln x5+C\] now we can find f(g(x))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F(x)=\frac x2+5\sqrt{x}+26\ln \sqrt{x}5+C\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looks good on the domain [0,25)u(25,infinity) as expected...

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0Oh I didn't realize this was Broken Fixer's question. lol

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0Broken Fixer knows everything.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F(x)`=\frac 12+5\frac{1}{2\sqrt{x}}+\frac{13}{\sqrt{x}(\sqrt{x}5)}\]
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