1) find d^2f/dx^2 when f(x) = x e^-7y+5y 2) find d^2f/dx dy when f(x) = x e^-8y+3y

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1) find d^2f/dx^2 when f(x) = x e^-7y+5y 2) find d^2f/dx dy when f(x) = x e^-8y+3y

Mathematics
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two different questions here question (1) find d^2f/dx^2when f(x) = x e^-7y+5y question (2) find d^2f/dx dy when f(x) = x e^-8y+3y
deriveing twice I assume
do we do partials? or implicits?

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well, since f(x) implies one variable id conjecture implicits
hmm since its wrt x and both are linear wrt x then the 2nd derivatives are 0
\[ x e^{-7y} + 5y\] by chance?
oh i was assuming partial
those groupings are a pain if you dont get them right
x e^(-7y) + 5y x' e^(-7y)+ x e^(-7y)' + 5 y' e^(-7y) -7x e^(-7y) y' + 5 y' then again
i have loads of these, need to be handed in ten minutes haha
the second one there suggests partials but its only a single variable
amistre, you are finding dy/dx not df/dx though
f(x) assumes that all variables are functions of x, so y = y(x)
the 2nd on tho says f(x) and wants f_xy
i think it should be written f(x,y) otherwise it would have asked for dy^2/dx right?
i think there might be some confusion as to whether f(x) IS y rather than written out is a rule with x(x) and y(x)
hard for me to parse the intricate details tho :)
agreed...salman little help?
its d^2f/dx dy the f(x)=xe^-8y+3y sorry chaps, this is the only info i have
ok, then assuming f(x) is not y, y is just another variable df/dx = e^-8y d/dy e^-8y = -8*e^-8y
for part a) df/dx = e^-7y d/dx e^-7y = 0

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