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anonymous
 4 years ago
show that the lines L1 and L2 are the same.
L1 is x=3t and y=1+2t
L2 is x=1+3t and y= 96t
anonymous
 4 years ago
show that the lines L1 and L2 are the same. L1 is x=3t and y=1+2t L2 is x=1+3t and y= 96t

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0......convert from parametric to regular than show they are the same...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so L1= P1(3,1) P2 (2,3) and L2= P1(1,9) P2( 2,3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why are the P1's not the same

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0\[L1={{3}\choose{1}}+t{{1}\choose{2}}\] \[L2={{1}\choose{9}}+t{{3}\choose{6}}\] \[L2=\frac{1}{3}{{3}\choose{27}}3t{{1}\choose{2}}\] you sure you aint got a typo in there?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0if they are the same line we can scale L2 or L1 to get the other one, but as is there seems to be an issue

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0for L1 we have:\[\begin{align} x&=3t\implies t=3x\\ y&=1+2t=1+2(3x)=1+62x=72x \end{align}\]for L2 we have:\[\begin{align} x&=1+3t\implies t=\frac{x+1}{3}\\ y&=96t=96(\frac{x+1}{3})=92(x+1)=92x2=72x \end{align}\]therefore L1 and L2 are the same line.
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