anonymous
  • anonymous
Would some one walk me through the steps to get this into quadratic form? I think I am over thinking it. q[2]/(-L+x)^2 = q[1]/x^2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TuringTest
  • TuringTest
this is q sub 1 and two as in charges I assume?\[q_1q_2\]right?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
I've gotten this far and then my algebra broke!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

TuringTest
  • TuringTest
Cross-multiply\[\frac{q_2}{(-L+x)^2}=\frac{q_1}{x^2}\to q_2x^2=q_1(-L+x)^2\]expand the second term\[q_2x^2=q_1(L^2-2Lx+x^2)= q_1L^2-2q_1Lx+q_1x^2\]gather like terms all on one side of the equals sign\[q_1x^2-q_2x^2-2q_1Lx+q_1L^2=0\]factor the x^2 to make the coefficient explicit:\[(q_1-q_2)x^2-2q_1Lx+q_1L^2=0\]now you should be able to identify a, b, and c for the quadratic formula.
anonymous
  • anonymous
OK, I see. I was stuck at the x^2 coefficients. Thanks!!!
TuringTest
  • TuringTest
welcome :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.