## anonymous 5 years ago Would some one walk me through the steps to get this into quadratic form? I think I am over thinking it. q[2]/(-L+x)^2 = q[1]/x^2

1. TuringTest

this is q sub 1 and two as in charges I assume?$q_1q_2$right?

2. anonymous

Yes

3. anonymous

I've gotten this far and then my algebra broke!

4. TuringTest

Cross-multiply$\frac{q_2}{(-L+x)^2}=\frac{q_1}{x^2}\to q_2x^2=q_1(-L+x)^2$expand the second term$q_2x^2=q_1(L^2-2Lx+x^2)= q_1L^2-2q_1Lx+q_1x^2$gather like terms all on one side of the equals sign$q_1x^2-q_2x^2-2q_1Lx+q_1L^2=0$factor the x^2 to make the coefficient explicit:$(q_1-q_2)x^2-2q_1Lx+q_1L^2=0$now you should be able to identify a, b, and c for the quadratic formula.

5. anonymous

OK, I see. I was stuck at the x^2 coefficients. Thanks!!!

6. TuringTest

welcome :)