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greenday will have to help you since they feel noone is capable of helping out ...

D is just the eugene values on the identity

I cant recall for the life of me what to do with the P tho

do you recall how to find the eugene values?

It is asking for the eigenvalues (diagonal entries of D) and eigenvectors (cols of P)

−1-L 4 −2
−3 4-L 0
−3 1 3-L
determinate of that and solve for L

i spose we could echlon it too to find out but i never get a good result that way

eugene vectors; thats the P .... ill remember that someday lol

−1 4 −2
−3 4 0
−3 1 3
−1 4 −2
0 -8 6
0 -11 9
−1 4 −2
0 -8 6
0 0 6/8
maybe?

L=-1
1+6+11+6 not= 0 ugh!!

maybe the eugenes are the negative diags? or i simply mismathed the whole thing

if we echoln the matrix, dont we get the Evalues as well? or is that just me wishful thinking?

that's a big help.

i know L=1 works by sheer luck, so whats left over is a quadratic

yeah, ill have to go over finding Evectors again to refresh me cobwebs :)

it may be from the augmented | A LI| gauss jordon stuff

(A+LI)X = 0

or simply
−1+L 4 −2
−3 4+L 0
−3 1 3+L
row reduced for each L

to find the evals solve
−1-L 4 −2
det −3 4-L 0 = 0
−3 1 3-L
as previously posted

http://www.sosmath.com/matrix/eigen2/eigen2.html
might be the same, hard for me to tell

i see,
AX = LX
AX - LX = 0
(A-LI)X = 0

they had a L = -4 which threw me for a loop :)