the tank is filled with salt water (specific weight=64 lb/ft^3) to a depth of 8ft. the pressure exerted by the water on the bottom of the tank, above atmospheric pressure is...

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the tank is filled with salt water (specific weight=64 lb/ft^3) to a depth of 8ft. the pressure exerted by the water on the bottom of the tank, above atmospheric pressure is...

Physics
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us measurement is confusing me...and the part that says "above atmospheric pressure"
so Pa doesn't equal 1.013*10^5 Pa??

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1 atm = 101.3 kPa
alright, so the statement in quotes mean nothing significant?
It does. Let me explain. \[P_{bottom} = P_{water} + P_{atm}\]\[P_{water} = \rho g h = SW*h\] \(P_{water}\) will have units pounds per square foot with the given data. Since we are considering the pressure about atmospheric at the bottom. Then\[P_{bottom} = SW*h\]We need to convert units\[P_{bottom} = SW * h \left [ \bf lb \over ft^2 \right ] * \left [\bf 1 ft^2 \over 144 i n^2 \right ]\]
SW=specific weight? so that replaces roh*g?
Yes.

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