## anonymous 4 years ago the tank is filled with salt water (specific weight=64 lb/ft^3) to a depth of 8ft. the pressure exerted by the water on the bottom of the tank, above atmospheric pressure is...

1. anonymous

2. anonymous

us measurement is confusing me...and the part that says "above atmospheric pressure"

3. anonymous

so Pa doesn't equal 1.013*10^5 Pa??

4. anonymous

1 atm = 101.3 kPa

5. anonymous

alright, so the statement in quotes mean nothing significant?

6. anonymous

It does. Let me explain. $P_{bottom} = P_{water} + P_{atm}$$P_{water} = \rho g h = SW*h$ $$P_{water}$$ will have units pounds per square foot with the given data. Since we are considering the pressure about atmospheric at the bottom. Then$P_{bottom} = SW*h$We need to convert units$P_{bottom} = SW * h \left [ \bf lb \over ft^2 \right ] * \left [\bf 1 ft^2 \over 144 i n^2 \right ]$

7. anonymous

SW=specific weight? so that replaces roh*g?

8. anonymous

Yes.