solve for for X and Y. given the that 4x^(2)-3Y=0 and 6X-2Y=3

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solve for for X and Y. given the that 4x^(2)-3Y=0 and 6X-2Y=3

Mathematics
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solve for y in the second equation so you have y=3x-3/2 then substitute y into the first equation. solve for x. when you have x substitute it in and solve for y
by substituting into the first equation you have 4x^2-3(3x-3/2)=0
i tried using substitution and but i solved for x in the frist equation getting x=\[(\sqrt{3y})/2\] then i plugged it into the 2nd equation and solved for y getting y=.75 and 3 is that i all that i need to?

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you can do that, but you have to remember that when you take a square root, you have to use the positive and the negative. that's why i used the second equation to solve for y and substituted that in, because it's simpler
ok makes sense thank you for your help
your welcome

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