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anonymous
 4 years ago
solve for for X and Y. given the that 4x^(2)3Y=0 and 6X2Y=3
anonymous
 4 years ago
solve for for X and Y. given the that 4x^(2)3Y=0 and 6X2Y=3

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve for y in the second equation so you have y=3x3/2 then substitute y into the first equation. solve for x. when you have x substitute it in and solve for y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0by substituting into the first equation you have 4x^23(3x3/2)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried using substitution and but i solved for x in the frist equation getting x=\[(\sqrt{3y})/2\] then i plugged it into the 2nd equation and solved for y getting y=.75 and 3 is that i all that i need to?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can do that, but you have to remember that when you take a square root, you have to use the positive and the negative. that's why i used the second equation to solve for y and substituted that in, because it's simpler

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok makes sense thank you for your help
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