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anonymous

  • 5 years ago

f(x) = 1-f(x-1) For positive integer x, if f(2)=12, then compute f(2006).

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  1. anonymous
    • 5 years ago
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    Oh god lol

  2. myininaya
    • 5 years ago
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    oops that x=2 one sec

  3. myininaya
    • 5 years ago
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    \[f(2)=1-f(2-1)=1-f(1)=12=> f(1)=-11\]

  4. myininaya
    • 5 years ago
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    \[f(3)=1-f(2)=1-12=-11\] \[f(4)=1-f(3)=1-(-11)=12\] \[f(5)=1-f(4)=1-12=-11\]

  5. anonymous
    • 5 years ago
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    Thank you! But what about f(2006)? I'm confused on how to incorporate that..

  6. myininaya
    • 5 years ago
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    i think there may be a pattern

  7. anonymous
    • 5 years ago
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    I see..

  8. myininaya
    • 5 years ago
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    \[f(6)=1-f(5)=1-(-11)=12\] \[f(7)=1-f(6)=1-12=-11\]

  9. myininaya
    • 5 years ago
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    see its either -11 or 12

  10. anonymous
    • 5 years ago
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    all odds are -11 evens are 12

  11. myininaya
    • 5 years ago
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    right

  12. anonymous
    • 5 years ago
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    Wow, thanks so much you guys! First time using this site and I love it already. (:

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