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anonymous
 4 years ago
An object is thrown vertically upward at 18 m/s from a window and hits the ground 1.6 s later. What is the height of the window above the ground? (Air resistance is negligible.) a. 3.7 m d. 37 m b. 16 m e. 41 m c. 21 m
anonymous
 4 years ago
An object is thrown vertically upward at 18 m/s from a window and hits the ground 1.6 s later. What is the height of the window above the ground? (Air resistance is negligible.) a. 3.7 m d. 37 m b. 16 m e. 41 m c. 21 m

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2You want to write down an equation for the position of the object at time t, call it y(t). y(t) = something involving initial velocity + something involving gravity. Then evaluate y(t=1.6 seconds) to find where the ground is.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2Hint: if there were no gravity, then y(t) = 18t Now, what does gravity do to that equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y(t)=18t5t^2 plugin value for time t=1.6s y=16m

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhhh!! is y(t) = Vi + g the equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why is y(t) = 18t  5t^2? What is the general equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://ibphysicsstuff.wikidot.com/uniformaccmotion it is equation8 that u are looking fo ALL THESE ARE FOR UNIFORMLY ACCELERATED MOTION
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