anonymous
  • anonymous
how do you complete the square on this 7x^2 + 10x = -2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
by keeping your wits about you
amistre64
  • amistre64
factor out the 7 on the left and work out the square part
anonymous
  • anonymous
divide by 7 first?

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amistre64
  • amistre64
\[7x^2+10x=-2\] \[7(x^2+\frac{10}{7}x)=-2\] \[7(x^2+\frac{10}{7}x+(\frac{10}{14})^2)=-2+7(\frac{10}{14})^2\]
amistre64
  • amistre64
then I spose we can get rid of that 7 by dividing both sides :)
amistre64
  • amistre64
\[x^2+\frac{10}{7}x+(\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2\] compact the left \[(x+\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2\] and work the rest thru
amistre64
  • amistre64
yes, divide off the 7 first :)
anonymous
  • anonymous
i can get to the point where i get (x = (10/14))^2 = 44/196 but dont know what to do after this
amistre64
  • amistre64
you sqrt the sides to unto the ^2 and add off the 10/14
anonymous
  • anonymous
is the answer (-5+ Sqrt11)-14
amistre64
  • amistre64
\[\sqrt{(x+\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2}\] \[x+\frac{10}{14}=\pm\sqrt{-\frac{2}{7}+(\frac{10}{14})^2}\] \[x=-\frac{10}{14}\pm\sqrt{-\frac{2}{7}+(\frac{10}{14})^2}\]
anonymous
  • anonymous
i mean (-5 + sqrt11)/14
amistre64
  • amistre64
the sqrt has 2 parts to it a + and a - that has to be accounted for
amistre64
  • amistre64
x^2 = 4 x = sqrt(4) x = 2, or -2
amistre64
  • amistre64
heres a simple dbl chk http://www.wolframalpha.com/input/?i=7x%5E2+%2B+10x+%3D+-2
amistre64
  • amistre64
looks to be a /7 not /14
anonymous
  • anonymous
ok thanks a mill
amistre64
  • amistre64
yep

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