how do you complete the square on this 7x^2 + 10x = -2

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how do you complete the square on this 7x^2 + 10x = -2

Mathematics
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by keeping your wits about you
factor out the 7 on the left and work out the square part
divide by 7 first?

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Other answers:

\[7x^2+10x=-2\] \[7(x^2+\frac{10}{7}x)=-2\] \[7(x^2+\frac{10}{7}x+(\frac{10}{14})^2)=-2+7(\frac{10}{14})^2\]
then I spose we can get rid of that 7 by dividing both sides :)
\[x^2+\frac{10}{7}x+(\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2\] compact the left \[(x+\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2\] and work the rest thru
yes, divide off the 7 first :)
i can get to the point where i get (x = (10/14))^2 = 44/196 but dont know what to do after this
you sqrt the sides to unto the ^2 and add off the 10/14
is the answer (-5+ Sqrt11)-14
\[\sqrt{(x+\frac{10}{14})^2=-\frac{2}{7}+(\frac{10}{14})^2}\] \[x+\frac{10}{14}=\pm\sqrt{-\frac{2}{7}+(\frac{10}{14})^2}\] \[x=-\frac{10}{14}\pm\sqrt{-\frac{2}{7}+(\frac{10}{14})^2}\]
i mean (-5 + sqrt11)/14
the sqrt has 2 parts to it a + and a - that has to be accounted for
x^2 = 4 x = sqrt(4) x = 2, or -2
heres a simple dbl chk http://www.wolframalpha.com/input/?i=7x%5E2+%2B+10x+%3D+-2
looks to be a /7 not /14
ok thanks a mill
yep

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