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anonymous
 4 years ago
Please help! Show me how to factor these binomials!
m^4256 and z^3+125, thank you! Descriptions are appreciated :)
anonymous
 4 years ago
Please help! Show me how to factor these binomials! m^4256 and z^3+125, thank you! Descriptions are appreciated :)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m^4256 this is a perfect square

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because 2*2=4, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the 1 you want to concentrate on is 256

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1try and get it into the form \(a^2b^2\) Use the hints that mth3v4 has given you.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1thx :) I'm actually an alien from another planet :D

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Starshine7  can you express 256 as (something)^2 ?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1good, now can you express \(m^4\) as (something)^2 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so can you put that in in a factored form

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, so \(m^4=(m^2)^2\) Now use those two to get the expression into the form \(a^2b^2\) so that you can then factor it like this:\[a^2b^2=(a+b)(ab)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why is it written like (m+number)(trinomial)? final answer i mean. If it helps, I factor by grouping if i can incorporate that somehow

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1just do this one step at a time and al will be revealed :)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Starshine7  are you stuck?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at the first answer you gave me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you come up with that ?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok, we saw above that:\[256=16^2\]\[m^4=(m^2)^2\]so now we can rewrite your original equation as:\[m^4256=(m^2)^216^2\]now mak use of:\[a^2b^2=(a+b)(ab)\]to simplify this further.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after that if can be factored again as an option as you can see

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(i think i am confusing starshine)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok, lets use a substitution to make it clearer...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1let \(n=m^2\), then we have:\[m^4256=(m^2)^216^2=n^216^2\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1we could use any other symbol  it doesn't really matter

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1the point is it is now in the form \(a^2b^2\)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1so you should now be able to factorise it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okies properties of exponents state when you multiply exponent and exponent you add the exponent values together (a^x)(a^b)=a^x+b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0exponent properties/laws of exponents whatever

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Starshine7  are you familiar with the exponent laws mth3v4 has shown? i.e.:\[(x^a)^b=x^{ab}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If it helps I dont understand when a and b are examples, I was taught using only the numbers, so thats why im really confused :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0those are just any number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know >_> Im weird like that

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1so you are comfortable with something like this:\[18^216^2=(18+16)(1816)\]but when replaced with symbols like this:\[a^2b^2=(a+b)(ab)\]you get lost?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok  the 'a' and 'b' are just placeholders for any number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just have attention issues so the numbers help me understand it better, i drift easily.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1what this says is that the formula:\[a^2b^2=(a+b)(ab)\]is true for ANY value of 'a' and 'b'

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1so in your example above, we ended up with:\[m^4256=(m^2)^216^2=n^216^2\]which means we can think of it as a=n and b=16 to get:\[n^216^2=(n+16)(n16)\]we can then substitute back \(n=m^2\) to get:\[m^4256=(n+16)(n16)=(m^2+16)(m^216)\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1do you understand those steps?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(a ^x ) ( a ^b )= a^x+b ^ ^ ^ ^ ^ ^ ^     /    L ________ L _ ___L_ _ L _ exponent number both x and b can be any number    your number ______ 

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does my funny drawing help XD

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok, so now you should notice that we have \((m^216)\) as one of the factors. since \(16=4^2\), we can write this as:\[(m^216)=(m^24^2)=(m+4)(m4)\]using the same formula. we therefore end up with:\[m^4256=(m^2+16)(m+4)(m4)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So you just keep factoring to the lowest numbers that are perfect squares?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1mth3v4  you have a lot of patience to draw all that :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it still comes out a bit messy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(a^x) (a^y) = a ^ x+y lemme try this you have this thing here right starshine?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Starshine7  for your second expression, you need to use the following factorisation:\[a^3+b^3=(a+b)(a^2ab+b^2)\]so you need to get your expression:\[z^3+125\]into the form \(a^3+b^3\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okies finish what you have first

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1I have to go now guys  Starshine I am sure mth3v4 will help you with the rest. Good luck all...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Aww..well bye Asna :) thanks anyways

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0z^3+125 is your next 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is not going to be squared but cubed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0have you heard of diff of cubes or sum of cubes formulas

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what ansa wrote there before leaving was formula for diff of cubes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because you just see just a 2 termed expression here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so how would you make x^3 and change it to x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0better yet lemme ask the question another way how do you get x^3 from x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not sure. I think they only have 2 exs in common

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okies lets try this ( a^x ) ( a^y ) = a ^ x +y the variable "a" can be any number 1, 2, 3, whatever, happy face , i dont care what you want it to be ok so far

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this just goes fot the variable "a" we good?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then next this for the variables "x, y" these give a numeric value (these have to be a number) giving a value ( a^x ) ( a^y) = a ^ x + y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so in the end the numeric value of your "a" exponent value "x" "a" exponent value "y" they add up result for the a ^ x + y is this more understandable?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so can we try that again how to get x^3 from x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just want it from x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sorry I have no idea what to do :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since it is already squared right (x^2)(x)=x how many more "x" do we need for x ^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but x^3 is made up of x^3 theres not anything left to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0remember (x^2)(x)=x? ^  value of exponent you are adding to the result

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol if there is nothing then say nothing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0be more sure of you self now just give the reason

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nm that its probably more difficult to explain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but do you understand how it works

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats all i want to know

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How about we start over with a new problem, m^3+216n^3 Show me in steps how to solve this and ill try another on my own, this might work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol this is differnt now because it has 2 variables in it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okie now we can use something called difference of squares a^3+b^3= (a+b) (a^2ab+b^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first of all you must clearly understand the laws of exponents (or at least the, 1 i showed you, you will have to use it for these problems )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we can go over it again i dont mind

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okie i will put a sample problem (x^3) (x^3 )=x ^6 the exponents values of "x " add up together (d ^100) ( d ^ 90) = d ^ 190 exponents values of "d" add up together

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does this make sense :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"for now" <note i can go over with the rest of the laws but i hhave limited time this is what you will need difference of squares a^3+b^3= (a+b) (a^2ab+b^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m^3+216n^3 know what you are working with m^3 + 216n^3 ^ ^ first term  second term

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a^3+b^3= ( a+b ) (a^2 ab+ b^2) ^ ^ you only have "items" that you are going to be multiplying using FOIL with

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a^3+b^3= (a+b) (a^2ab+b^2)  ^ ^  this part wants the numbers squared to  be multiplied with L

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do we get a squared variable to be cubed? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0type how you would do that plz :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its correct but how would it look

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0give you a hint its not x+x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is called adding like terms

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0remember this model (a ^ x) ( a ^y ) = a ^x+y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x is going to be your a variable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the values of your exponent to the x are?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i gave you already x^2 you have x^2 how much you need to get to x^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(x ^ 2) ( x ^y ) = x ^2+y what will you need to get 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as the exponent result

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the value of that 1 that you are missing is just x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is because x*x*x = x^3 but i think you know that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know how to simplify radicals

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im sorry i have chat lag :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cube root of 216 is 6 but you want 6^2 and n^2 so you can do the FOIL
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