anonymous
  • anonymous
Can someone help me with LU factorization?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
lowers and uppers
Hero
  • Hero
Well, at least I know what LU stands for now.
amistre64
  • amistre64
:)

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More answers

anonymous
  • anonymous
|dw:1327272671601:dw|
anonymous
  • anonymous
lol that looks terrible
amistre64
  • amistre64
the upper is the echelon form with leading 1s
anonymous
  • anonymous
can u show how upper and lower will kinf od look
anonymous
  • anonymous
like where the 0s and ones will be
amistre64
  • amistre64
-2 1 ~ 1 -1/2 ~ 1 -1/2 ~ 1 -1/2 -6 4 ~ -1 4/6 ~ 0 1/6 ~ 0 1 should be the U
anonymous
  • anonymous
ok
amistre64
  • amistre64
i gotta reread up on the L part, it starts with the same column but somehow the others are changed up
amistre64
  • amistre64
-2 0 6 ? is the L
amistre64
  • amistre64
might be the -1/6 part tho let me read up on that
anonymous
  • anonymous
idk it is confusing in a 2by 2 matrix
anonymous
  • anonymous
much simpler with 3 by 3
amistre64
  • amistre64
to get a 1 in the ? we multiplied by 6 ....
anonymous
  • anonymous
ok THANKS
anonymous
  • anonymous
I am gonna do it on my own and see if I get the same answer :D
anonymous
  • anonymous
rld you would better solve ur problem than loling in mine :P
amistre64
  • amistre64
-2 1 -6 4 -6(1 -1/2 6 4 -6 3 ------ 0 7 this one might do better for us -2 1 -6 7 is part of the process
anonymous
  • anonymous
ok I thought u use the elementary row operations
anonymous
  • anonymous
I got a different answer
anonymous
  • anonymous
|dw:1327273667252:dw|
anonymous
  • anonymous
This is what i go t using the elementary row operations
amistre64
  • amistre64
i did, you wanna 1 out A first, and keep track of those pivots before you change them; they are the diagonals of your L
amistre64
  • amistre64
but how to go about the L after that I cant recall just yet; theres a book upstairs i might be able to read up on since thats where I learned it :)
anonymous
  • anonymous
amistre come help me now
anonymous
  • anonymous
LOL dont drive urself crazy LOL
anonymous
  • anonymous
Go help tomas seriously
amistre64
  • amistre64
ok, good luck. im going to be going thru this in a few weeks for linearA as well
phi
  • phi
when you do LU decomposition, you use elimination to find U to find L, keep track of the multiplier you use to eliminate the "key position" -2 1 -6 4 use -3 to get rid of the 2nd row, 1st col (scale 1st row by -3 and add to 2nd row): -2 1 0 1 Now put the negative of -3 in the key position of the identity matrix: 1 0 3 1 You now have L and U
anonymous
  • anonymous
Thanks that helped out :D

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