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anonymous
 4 years ago
Can someone help me with LU factorization?
anonymous
 4 years ago
Can someone help me with LU factorization?

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Well, at least I know what LU stands for now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327272671601:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol that looks terrible

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the upper is the echelon form with leading 1s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show how upper and lower will kinf od look

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like where the 0s and ones will be

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.02 1 ~ 1 1/2 ~ 1 1/2 ~ 1 1/2 6 4 ~ 1 4/6 ~ 0 1/6 ~ 0 1 should be the U

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0i gotta reread up on the L part, it starts with the same column but somehow the others are changed up

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0might be the 1/6 part tho let me read up on that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk it is confusing in a 2by 2 matrix

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0much simpler with 3 by 3

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0to get a 1 in the ? we multiplied by 6 ....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am gonna do it on my own and see if I get the same answer :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rld you would better solve ur problem than loling in mine :P

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.02 1 6 4 6(1 1/2 6 4 6 3  0 7 this one might do better for us 2 1 6 7 is part of the process

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I thought u use the elementary row operations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got a different answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327273667252:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is what i go t using the elementary row operations

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0i did, you wanna 1 out A first, and keep track of those pivots before you change them; they are the diagonals of your L

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0but how to go about the L after that I cant recall just yet; theres a book upstairs i might be able to read up on since thats where I learned it :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0amistre come help me now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0LOL dont drive urself crazy LOL

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Go help tomas seriously

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0ok, good luck. im going to be going thru this in a few weeks for linearA as well

phi
 4 years ago
Best ResponseYou've already chosen the best response.2when you do LU decomposition, you use elimination to find U to find L, keep track of the multiplier you use to eliminate the "key position" 2 1 6 4 use 3 to get rid of the 2nd row, 1st col (scale 1st row by 3 and add to 2nd row): 2 1 0 1 Now put the negative of 3 in the key position of the identity matrix: 1 0 3 1 You now have L and U

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks that helped out :D
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