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anonymous

  • 4 years ago

Can someone help me with LU factorization?

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  1. amistre64
    • 4 years ago
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    lowers and uppers

  2. Hero
    • 4 years ago
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    Well, at least I know what LU stands for now.

  3. amistre64
    • 4 years ago
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    :)

  4. anonymous
    • 4 years ago
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    |dw:1327272671601:dw|

  5. anonymous
    • 4 years ago
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    lol that looks terrible

  6. amistre64
    • 4 years ago
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    the upper is the echelon form with leading 1s

  7. anonymous
    • 4 years ago
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    can u show how upper and lower will kinf od look

  8. anonymous
    • 4 years ago
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    like where the 0s and ones will be

  9. amistre64
    • 4 years ago
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    -2 1 ~ 1 -1/2 ~ 1 -1/2 ~ 1 -1/2 -6 4 ~ -1 4/6 ~ 0 1/6 ~ 0 1 should be the U

  10. anonymous
    • 4 years ago
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    ok

  11. amistre64
    • 4 years ago
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    i gotta reread up on the L part, it starts with the same column but somehow the others are changed up

  12. amistre64
    • 4 years ago
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    -2 0 6 ? is the L

  13. amistre64
    • 4 years ago
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    might be the -1/6 part tho let me read up on that

  14. anonymous
    • 4 years ago
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    idk it is confusing in a 2by 2 matrix

  15. anonymous
    • 4 years ago
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    much simpler with 3 by 3

  16. amistre64
    • 4 years ago
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    to get a 1 in the ? we multiplied by 6 ....

  17. anonymous
    • 4 years ago
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    ok THANKS

  18. anonymous
    • 4 years ago
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    I am gonna do it on my own and see if I get the same answer :D

  19. anonymous
    • 4 years ago
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    rld you would better solve ur problem than loling in mine :P

  20. amistre64
    • 4 years ago
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    -2 1 -6 4 -6(1 -1/2 6 4 -6 3 ------ 0 7 this one might do better for us -2 1 -6 7 is part of the process

  21. anonymous
    • 4 years ago
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    ok I thought u use the elementary row operations

  22. anonymous
    • 4 years ago
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    I got a different answer

  23. anonymous
    • 4 years ago
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    |dw:1327273667252:dw|

  24. anonymous
    • 4 years ago
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    This is what i go t using the elementary row operations

  25. amistre64
    • 4 years ago
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    i did, you wanna 1 out A first, and keep track of those pivots before you change them; they are the diagonals of your L

  26. amistre64
    • 4 years ago
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    but how to go about the L after that I cant recall just yet; theres a book upstairs i might be able to read up on since thats where I learned it :)

  27. anonymous
    • 4 years ago
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    amistre come help me now

  28. anonymous
    • 4 years ago
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    LOL dont drive urself crazy LOL

  29. anonymous
    • 4 years ago
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    Go help tomas seriously

  30. amistre64
    • 4 years ago
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    ok, good luck. im going to be going thru this in a few weeks for linearA as well

  31. phi
    • 4 years ago
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    when you do LU decomposition, you use elimination to find U to find L, keep track of the multiplier you use to eliminate the "key position" -2 1 -6 4 use -3 to get rid of the 2nd row, 1st col (scale 1st row by -3 and add to 2nd row): -2 1 0 1 Now put the negative of -3 in the key position of the identity matrix: 1 0 3 1 You now have L and U

  32. anonymous
    • 4 years ago
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    Thanks that helped out :D

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