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anonymous
 4 years ago
How to prove that in group of 6 people there are at least 2 people who has same amount of friends among that group?
anonymous
 4 years ago
How to prove that in group of 6 people there are at least 2 people who has same amount of friends among that group?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0R u sure it cld be proved

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see didnt read the question correctly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's classical problem and i have proved it somehow but i don't remember anymore

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0do the 6 people even have to be friends? after all, a group of 6 strangers is still a group of 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, but if they don't have any friends there will be 6 people who have no friends

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0if 2 people in the group are friends; then at least 2 people have 1 friend .... something like that

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0if 3 people are friends, then a > bc, b > ac, c>ba

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0thats at least 2 with the same amount of friends

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0or even a>c , c>b, c>ab

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i translated it from lithuanian but it seems it has same meaning

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0can 2 people be not friends? if one of them is a friend?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2oh wait, I see. Let f(n) be the number of friends in that group that the nth person has. For each n, \[ 0 \leq f(n) \leq 5 \] Therefore ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0a>c, b>c , c>ab is what i meant lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes there can be no friends at all or 1 person can have no friends

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0I think James has it :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0even if 4 are friends, that still leaves 2 with 0 friends each which is the same amount

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2there are 6 values for f(1), f(2), f(3), f(4), f(5), f(6). Now it can't be that these six number take on all of 0,1,2,3,4,5. Because if f(n) = 5 for one n, then f(j) > 0 for all other \( j \neq n \). Hence in fact, there are only 5 possible values for f(n). But as there are six f(n), at least two of the f(n) must be equal.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0ill concede to that answer as well ;)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0my by case proof could get lengthy

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0gotta hang it on the left to be a valid q lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0and I gotta get my ode hw written up so ciao yall :)
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