## Alison123 5 years ago how do you solve 2/3 x squared + x= 4 + 2/3

1. anonymous

This? $\frac{2}{3}x^{2}+x= 4+\frac{2}{3}$

2. Alison123

yeah that

3. anonymous

When you have a polynomial like this, you want to get everything on one side so it equals 0:$\frac{2}{3}x^{2} + x = \frac{14}{3}$$\frac{2}{3}x^{2} + \frac{3}{3}x - \frac{14}{3} = 0$ Then to make it easier, you can divide the whole thing by 3:$2x^{2} + 3x -14 = 0$ Then you can factor it:$(2x+7)(x-2)=0$ And now it can be solved, because for this to be zero, at least one of the parentheses needs to equal 0. So solve the first parentheses: $(2x+7) = 0$$2x = -7$$x = -\frac{7}{2}$ Then the 2nd:$(x-2) = 0$$x=2$ So you have 2 values that would work for x: -7/2 and 2