anonymous
  • anonymous
2x-3y=5 10x+10y=30 what is the solution?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Multiply first equation by 5. Then add.
myininaya
  • myininaya
how about -5 and then after add the equations
myininaya
  • myininaya
5 is fine we would just have to subtract which is fine

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anonymous
  • anonymous
It should be subtract. Anyway, once you multiply by 5, it will be clear whether to add or subtract to eliminate x. At least I hope.
anonymous
  • anonymous
please elaborate
myininaya
  • myininaya
\[-10x+30y=-25\] multiplying the top equation by -5 gives us that
myininaya
  • myininaya
now add this to 10x+10y=30
anonymous
  • anonymous
whats the answer
myininaya
  • myininaya
add those equations (-10x+10x)+(30y+10y)=(-25+30)
myininaya
  • myininaya
\[40y=5 => y=\frac{5}{40}\] reduced then plug into one of the equations given and solve for x
myininaya
  • myininaya
sorry i multiplied wrong at first the equation was suppose to be -10x+15y=-25 after multiplying the -5
myininaya
  • myininaya
now add the equations together
anonymous
  • anonymous
i dont remember my teacher explaining it like that.. o.o
myininaya
  • myininaya
\[-10x+15y=-25\] \[10x+10y=30\] ---------------- 0x+25y=5 25y=5 now divide by 25 on both sides then reduce the fraction then plug into one of the equations given and solve for x

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