If f(2)=6, f'(2)=-4, and f"(2)=2, what is (d^2*(f^3 (x)))/(dx^2 ) at x=2?

If f(2)=6, f'(2)=-4, and f"(2)=2, what is (d^2*(f^3 (x)))/(dx^2 ) at x=2?

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\[\frac{d^2([f(x)]^3)}{dx^2}\]
\[=\frac{d}{dx}(3[f(x)]^2f'(x))=3[2f(x)f'(x)f'(x)+[f(x)]^2f''(x)]\]

\[3[f(2)f'(2)f'(2)+[f(2)]^2f''(2)]\]

now plug in and evaluate and simplify

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