karatechopper
  • karatechopper
GT please help in Trig
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Look at this link: http://en.wikipedia.org/wiki/Sine Particularly section "Relation to Unit Circle". In trignometry, sine and cosine are two basic functions. Their values are defined as ratios of sides of right triangle (formed inside the unit circle) based on various angle measures.
karatechopper
  • karatechopper
ok..then..
anonymous
  • anonymous
Really, first study that part and ask questions. If you understand this basic point, rest is all bunch of re-arranging and playing with it.

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karatechopper
  • karatechopper
ok
karatechopper
  • karatechopper
well i do have one question, but its not only a sine question its a cos,sin, and tan question. may i ask?
anonymous
  • anonymous
|dw:1327282151207:dw|
anonymous
  • anonymous
Ask any question any time.
karatechopper
  • karatechopper
ok well how do you know if you have to solve for sin, cos, or tan? i see that some questions dont tell you..
anonymous
  • anonymous
In that above triangle sin(x) = a/c cos(x) = b/c In unit circle, c = 1 (radius of that unit circle).
anonymous
  • anonymous
tan is nothing but ratio of "sin and cos" tan = sin/cos
anonymous
  • anonymous
What function you solve for depends on the triangle's angles and measures in question. In my triangle above, x is the specific angle in the left bottom. If x was the right top angle, then sin and cos will "flip".
anonymous
  • anonymous
In general: sin = opposite side of angle / hypotenuse cos = adjacent side of angle / hypotenuse
anonymous
  • anonymous
|dw:1327282536012:dw|
anonymous
  • anonymous
sin(x) = a/c cos(x) = b/c tan(x) = sin(x)/cos(x) = a/c / b/c = a/b sin(y) = b/c cos(y) = a/c tan(y) = sin(y)/cos(y) = b/c / a/c = b/a
karatechopper
  • karatechopper
?
anonymous
  • anonymous
what?

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