Give an equestion for the line that contains ( 3,2 ) and (5,-2 )

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Give an equestion for the line that contains ( 3,2 ) and (5,-2 )

Mathematics
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Slope = (-2-2)/(3-5)=-4/-2=2 So now we know the slope is 2 plug one of the points and the slope into point-slope form.
Can you do that?
I Dont Get It

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find slope m = y2 - y1 / x2 - x1 m = -2 - 2 / 5 - 3 m =-4 / 2 m = -2 find b y = mx + b pick any coordinate 2 = -2 (3) + b 2 = -6 + b 8 = b your equation is y = -2x + 8
Here is point-slope form: y-y1=m(x-x1)
Ok. Dada will help you, I see.
lol i showed all the steps so you can learn from it I believe Mertsj is right you should learn how to do it yourself
How would you grap that
most basic graphing is to fill in some xs to find the ys to plot
the equation is a rule for the graph; all it has to be be is followed
another simpler way is to plot the 2 points given and draw a line between them
but how would you do that
the equation itself just defines the line;
they gave you 2 points right? you know how to plot a point?
|dw:1327282532053:dw|
no i dont know how to plot a point
good, the first number is how far you move on the x; the second is how far you go on the y
so can you draw for me how to do this please
|dw:1327282661108:dw|
can you plot the other one with those instructions?
(5,-2) over 5 and down 2
|dw:1327282745683:dw|
does that make sense?
|dw:1327282794427:dw| then connect the dots

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