a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=-7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds

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a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=-7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds

Mathematics
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whats the question here singh?
your gonna awnser it
a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=-7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds

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H=-7t^2 + 42t + 49 H=0, When -7t^2 + 42t + 49=0, t=7sec and t=-1sec so after 7 sec the toy rocket is in the ground
how long after the launch did the rocket hit the ground explain
after t=7sec the rocket hits the ground
what time has passed when the rocket has reached its highest point
H=-7t^2 + 42t + 4=0, that is solving for t in sec
may i know if you are in the calculus class or algebra?
algebra
ya so whats the awnser
what time has passed when the rocket has reached its highest point
ok... from H=-7t^2 + 42t + 49, this is a quadratic equation and a=-17,b=42 and c=49... the velocity equation is V=2ax+b=2(-7)t+42=-14t+42 now at max height V=0=-14t+42 we get t=3sec that is when the rocket reached its max height and the max height H=-7(3)^2 +42(3)+49=112 metres answer
any question?
Explain what happens to the graph of the exponential relation 2^x to the right of the y axis?
meant to say 2 to the power of x
?
are u there

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