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anonymous
 4 years ago
a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds
anonymous
 4 years ago
a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats the question here singh?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a toy rocket is pumped full of air and released upward. Its height can be approximated using the relation H=7t squared + 42t + 49 where h is the height above ground in metres and t is the time in seconds

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0H=7t^2 + 42t + 49 H=0, When 7t^2 + 42t + 49=0, t=7sec and t=1sec so after 7 sec the toy rocket is in the ground

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how long after the launch did the rocket hit the ground explain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after t=7sec the rocket hits the ground

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what time has passed when the rocket has reached its highest point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0H=7t^2 + 42t + 4=0, that is solving for t in sec

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0may i know if you are in the calculus class or algebra?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya so whats the awnser

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what time has passed when the rocket has reached its highest point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok... from H=7t^2 + 42t + 49, this is a quadratic equation and a=17,b=42 and c=49... the velocity equation is V=2ax+b=2(7)t+42=14t+42 now at max height V=0=14t+42 we get t=3sec that is when the rocket reached its max height and the max height H=7(3)^2 +42(3)+49=112 metres answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Explain what happens to the graph of the exponential relation 2^x to the right of the y axis?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0meant to say 2 to the power of x
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