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askme12345 Group Title

STATISTICS

  • 2 years ago
  • 2 years ago

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  1. askme12345 Group Title
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    1. A physician wanted to estimate the mean length of time that a patient had to wait to see him after arriving at the office. A random sample of 36 patients showed a mean waiting time of 23.4 minutes and a standard deviation of 7.2 minutes. Find a 96% confidence interval for .

    • 2 years ago
  2. amistre64 Group Title
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    sd/sqrt(n) sounds familiar

    • 2 years ago
  3. amistre64 Group Title
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    \[z=\frac{x-mean}{sd/\sqrt{n}}\]

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  4. amistre64 Group Title
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    where z is the value at Za = .02 maybe?

    • 2 years ago
  5. amistre64 Group Title
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    |dw:1327284026014:dw|

    • 2 years ago
  6. amistre64 Group Title
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    i know im missing something :/

    • 2 years ago
  7. amistre64 Group Title
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    we want the interval of Lx to Rx right?

    • 2 years ago
  8. amistre64 Group Title
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    z = 2.06 if i see the table right

    • 2 years ago
  9. amistre64 Group Title
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    \[z=\frac{x-mean}{sd/\sqrt{n}}\] \[z(sd/\sqrt{n})={x-mean}\] \[z(sd/\sqrt{n})+mean={x}\] \[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the right}\] \[-2.06(7.2/\sqrt{36})+23.4={x}\text{ to the left}\]

    • 2 years ago
  10. amistre64 Group Title
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    with any luck that is :) im sure im forgetting something important tho

    • 2 years ago
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