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askme12345 Group TitleBest ResponseYou've already chosen the best response.0
1. A physician wanted to estimate the mean length of time that a patient had to wait to see him after arriving at the office. A random sample of 36 patients showed a mean waiting time of 23.4 minutes and a standard deviation of 7.2 minutes. Find a 96% confidence interval for .
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
sd/sqrt(n) sounds familiar
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
\[z=\frac{xmean}{sd/\sqrt{n}}\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
where z is the value at Za = .02 maybe?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
dw:1327284026014:dw
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
i know im missing something :/
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
we want the interval of Lx to Rx right?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
z = 2.06 if i see the table right
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
\[z=\frac{xmean}{sd/\sqrt{n}}\] \[z(sd/\sqrt{n})={xmean}\] \[z(sd/\sqrt{n})+mean={x}\] \[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the right}\] \[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the left}\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
with any luck that is :) im sure im forgetting something important tho
 2 years ago
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