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askme12345
 3 years ago
Best ResponseYou've already chosen the best response.01. A physician wanted to estimate the mean length of time that a patient had to wait to see him after arriving at the office. A random sample of 36 patients showed a mean waiting time of 23.4 minutes and a standard deviation of 7.2 minutes. Find a 96% confidence interval for .

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0sd/sqrt(n) sounds familiar

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[z=\frac{xmean}{sd/\sqrt{n}}\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0where z is the value at Za = .02 maybe?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1327284026014:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0i know im missing something :/

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0we want the interval of Lx to Rx right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0z = 2.06 if i see the table right

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[z=\frac{xmean}{sd/\sqrt{n}}\] \[z(sd/\sqrt{n})={xmean}\] \[z(sd/\sqrt{n})+mean={x}\] \[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the right}\] \[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the left}\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0with any luck that is :) im sure im forgetting something important tho
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