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Plot the points and use pythagorean theorem or distance formula

thats what the last person told me and apparently i am not doing something right

You have graph paper right?

no i am doing it all on computer

Do you have a graphic plotting device on your computer?

you shouldn't do math without graph paper handy. Math 101

Label the points and plug them in. It's easy

ok let me see here give me a sec.

when it comes to x1 and x2 does it matter which x # I put where

yes it does

label your points like this:
(x1,y1) (x2, y2)

ok so I would insert -3 in the x2 spot right

ok now im confused

okay, let me show you

(x1,y1) = (-3,5)
(x2,y2) = (6,-2)
Is that clear enough?

so when it says x2 or y2 that just means its place and not to the 2nd power

yes, correct

ok give me a sec

Ok when I plug them all in I got sqrt((6-(-3))^2+(-2-(-5)^2=(3)^2+(3)^2=9+9=81

You did something wrong. For that first one (6-(-3)^2 = (6+3)^2 = 9^2, not 3^2

This is why graphing method is better

But also 9+9 = 18 , not 81. You're supposed to add at the end not multiply

Ok so the 2nd 1 would be (-2-(-5)^2=(7)^2=14

You had the second one right already ....face palm :P

(-2-(-5))^2 = (-2+5)^2 = (3)^2 = 9

so my points would be (18,9)

You're not trying to find anymore points. You're trying to find DISTANCE

ok so what do i have to do from here

And post your steps just like last time. Just be more careful

what do you mean

i meant for you to try to calculate it again. But try to add correctly this time.

it would b 6 and not 9

the answer is d = 3root(10). Try to figure out how I got that

that would be 130