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Plot the points and use pythagorean theorem or distance formula
thats what the last person told me and apparently i am not doing something right
You have graph paper right?
no i am doing it all on computer
Do you have a graphic plotting device on your computer?
no we are not allowed to do it that way. I meant my assignment is on computer. I am having to do it all on paper and show all of my work
you shouldn't do math without graph paper handy. Math 101
ok I will remember that....i have the distance formula as sqrt((x2-x1)^2+(y2-y1)^2) but I do not know how to put everything into that formula or where to go from there
Label the points and plug them in. It's easy
ok let me see here give me a sec.
when it comes to x1 and x2 does it matter which x # I put where
yes it does
label your points like this: (x1,y1) (x2, y2)
ok so I would insert -3 in the x2 spot right
ok now im confused
okay, let me show you
(x1,y1) = (-3,5) (x2,y2) = (6,-2) Is that clear enough?
so when it says x2 or y2 that just means its place and not to the 2nd power
ok give me a sec
Ok when I plug them all in I got sqrt((6-(-3))^2+(-2-(-5)^2=(3)^2+(3)^2=9+9=81
You did something wrong. For that first one (6-(-3)^2 = (6+3)^2 = 9^2, not 3^2
This is why graphing method is better
But also 9+9 = 18 , not 81. You're supposed to add at the end not multiply
Ok so the 2nd 1 would be (-2-(-5)^2=(7)^2=14
You had the second one right already ....face palm :P
(-2-(-5))^2 = (-2+5)^2 = (3)^2 = 9
so my points would be (18,9)
You're not trying to find anymore points. You're trying to find DISTANCE
ok so what do i have to do from here
Basically, when you calculated it the first time, you made a couple of adding mistakes. That's all. Try it again.
And post your steps just like last time. Just be more careful
what do you mean
i meant for you to try to calculate it again. But try to add correctly this time.
it would b 6 and not 9
the answer is d = 3root(10). Try to figure out how I got that
that would be 130