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anonymous
 4 years ago
Find the area of the region bounded by the curves f(x)=(3x+1)^2 g(x)=2^0.4x i checked my work a lot of times but I couldn't get 8.3522
anonymous
 4 years ago
Find the area of the region bounded by the curves f(x)=(3x+1)^2 g(x)=2^0.4x i checked my work a lot of times but I couldn't get 8.3522

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, I'm going to try this one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh thanks. May be I better show you what i have done so you can find my mistakes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sounds good. I'm looking at the graphs right now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327278455526:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that what you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1.259}^{0.62} 2^{0.4x}[(3x+1)^{2}7]dx \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left[ (2^{0.4x}/0.4\ln2  3x ^{3}3x ^{2}+6x \right] \]\[\int\limits_{1.259}^{0.62} 2^{0.4x}9x ^{2}6x+6 dx\]\[\int\limits_{1.259}^{0.62}2^{0.4x}[9x ^{2}+6x+17]dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left[ 2^{0.4x}/0.4\ln2  3x ^{3}3x ^{2}+6x \right]\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, it's taking me some time to check the algebra/arithmetic. :) But so far your approach looks good.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's okay :) I can't find what's wrong here :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh btw did I get the interval right? [1.259, 0.62]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Did you get those values by setting the equations equal to themselves and solving for x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No. I got it from calculator. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, I have to admit that I was having difficulty solving the equation, but what I did was put it into wolframalpha.com\[9x ^{2}+6x+1=2^{0.4x}\] It gave me x=0 and 1.246 E 8. This is the link: http://www.wolframalpha.com/input/?i=9x%5E2%2B6x%2B1%3D2%5E%28.4x%29

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i just look at the intersections of f(x) and g(x) on calculator. I'm confused now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, never mind what I said if that confuses you. When I look at my calculator I get [0.64, 0].

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh my bad. I typed a wrong equation f(x)=(3x+1)^2 7 sorry sorry sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No problem! Glad you found your mistake. Let's try it with these limits.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Don't be! I just started this too and have made errors that are much worse :) It has helped me to work through this with you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hehe this problem takes me like more than one hour to find the answer that my teacher stated.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my answer is 9.913 do you get the same one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is my equation:\[\int\limits_{0.64bj }^{0}2^{0.4x}(9x+6x+1) dx\] My answer is way off, I got 3.018

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you didn't change the equation, did you? cuz it's supposed to be 9x+6x+17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0My bad it is supposed to be\[9x ^{2}\], but where did the 7 come from? I didn't see it in the original equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just said that I typed a wrong equation f(x)=(3x+1)^27 :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok now I get it so it is\[\int\limits\limits_{0.64}^{0}2^{0.4x}( 9x3x+17) dx \]which equals\[\int\limits_{0.64}^{0}2^{0.4x}9x+3x+6dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup but the interval is different cuz you changed the equation. You should check the intersections with your calculator too.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey wait it is \[2^{0.4x}9x ^{2}6x+6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You are right, I meant 6x. So are you saying that the minus sign is already distributed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So I should take it out when I plug it in to my calculator.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yup. Did you find the interval?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here we go: [1.277,0.63] . However, the first number is not exact.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmmm this is why I think an equation is better if only I could solve it correctly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But I think we are in the ballpark. This was tricky with the x in the exponent.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you're trying to find the interval by solving the equations? I can't find it by hand, you know.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, well I was estimating at first; I get the same answer that you did using the calc function.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes then we just need to integrate that equation. I started over and get 9.913

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The integration is fine. I used all of the digits for the intersection and got 6.702.
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