At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Ok, I'm going to try this one.

oh thanks. May be I better show you what i have done so you can find my mistakes

Sounds good. I'm looking at the graphs right now.

|dw:1327278455526:dw|

is that what you get?

\[\int\limits_{-1.259}^{0.62} 2^{0.4x}-[(3x+1)^{2}-7]dx \]

\[\left[ 2^{0.4x}/0.4\ln2 - 3x ^{3}-3x ^{2}+6x \right]\]

it's okay :) I can't find what's wrong here :(

oh btw did I get the interval right? [-1.259, 0.62]

Did you get those values by setting the equations equal to themselves and solving for x?

No. I got it from calculator. :)

well i just look at the intersections of f(x) and g(x) on calculator. I'm confused now.

Ok, never mind what I said if that confuses you. When I look at my calculator I get [-0.64, 0].

oh my bad. I typed a wrong equation f(x)=(3x+1)^2 -7 sorry sorry sorry

No problem! Glad you found your mistake. Let's try it with these limits.

:) I'm so sorry.

hehe this problem takes me like more than one hour to find the answer that my teacher stated.

my answer is 9.913 do you get the same one?

Almost have it . . .

you didn't change the equation, did you? cuz it's supposed to be 9x+6x+1-7

I mean question.

i just said that I typed a wrong equation f(x)=(3x+1)^2-7 :)

Is this right?

Oh yes

hey wait it is \[2^{0.4x}-9x ^{2}-6x+6\]

You are right, I meant 6x. So are you saying that the minus sign is already distributed?

Yes

So I should take it out when I plug it in to my calculator.

Yup. Did you find the interval?

Here we go: [-1.277,0.63] . However, the first number is not exact.

I got [-1.259, 0.62]

hmmm this is why I think an equation is better if only I could solve it correctly.

But I think we are in the ballpark. This was tricky with the x in the exponent.

you're trying to find the interval by solving the equations? I can't find it by hand, you know.

Ok, well I was estimating at first; I get the same answer that you did using the calc function.

yes then we just need to integrate that equation. I started over and get 9.913

The integration is fine. I used all of the digits for the intersection and got 6.702.