find the equation of the tangent line to y=x^2+3x from point 0,-1 show your work

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find the equation of the tangent line to y=x^2+3x from point 0,-1 show your work

Mathematics
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what y'?
the slope of the tangent line is equal to the derivative of "y"
once we know the slope, the rest is natural

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Other answers:

that's all
there's nothing more
then we should find the derivative of y.
how do you do that?
could you teach me how?
practice makes perfect; the question suggests that you should be familiar with the derivative in some way; i can go thru some simple shortcuts for you
but to teach you derivatives is beyond the scope of this environment
alright
y=x^2+3x the derivative of a sum is the sum of the derivatives y' = x^2' + 3x'
the derivative of x^n = nx^{n-1} for example: x^5 = 5x^4
from this, what would you deduce is the derivative of x^2?
what you just explained made no sense to me
but don't worry about it
im not at the level math u r
you taking calculus yet?
nope
thats where you learn about derivatives :)
:)
at any rate; if you knew the derivative got us to 2x+3; this would tell us the equation of the slope at any given point on our line
at x=0 this slope = 3
given a slope and a point we can construct a line: y = mx -mPx + Py y = 3x -3(0) +-1 y = 3x -1 looks to be it
good luck with it :)
ok, thanks

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