anonymous
  • anonymous
find the equation of the tangent line to y=x^2+3x from point 0,-1 show your work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
what y'?
amistre64
  • amistre64
the slope of the tangent line is equal to the derivative of "y"
amistre64
  • amistre64
once we know the slope, the rest is natural

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anonymous
  • anonymous
that's all
anonymous
  • anonymous
there's nothing more
amistre64
  • amistre64
then we should find the derivative of y.
anonymous
  • anonymous
how do you do that?
anonymous
  • anonymous
could you teach me how?
amistre64
  • amistre64
practice makes perfect; the question suggests that you should be familiar with the derivative in some way; i can go thru some simple shortcuts for you
amistre64
  • amistre64
but to teach you derivatives is beyond the scope of this environment
anonymous
  • anonymous
alright
amistre64
  • amistre64
y=x^2+3x the derivative of a sum is the sum of the derivatives y' = x^2' + 3x'
amistre64
  • amistre64
the derivative of x^n = nx^{n-1} for example: x^5 = 5x^4
amistre64
  • amistre64
from this, what would you deduce is the derivative of x^2?
anonymous
  • anonymous
what you just explained made no sense to me
anonymous
  • anonymous
but don't worry about it
anonymous
  • anonymous
im not at the level math u r
amistre64
  • amistre64
you taking calculus yet?
anonymous
  • anonymous
nope
amistre64
  • amistre64
thats where you learn about derivatives :)
anonymous
  • anonymous
:)
amistre64
  • amistre64
at any rate; if you knew the derivative got us to 2x+3; this would tell us the equation of the slope at any given point on our line
amistre64
  • amistre64
at x=0 this slope = 3
amistre64
  • amistre64
given a slope and a point we can construct a line: y = mx -mPx + Py y = 3x -3(0) +-1 y = 3x -1 looks to be it
amistre64
  • amistre64
good luck with it :)
anonymous
  • anonymous
ok, thanks

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