A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

Prove that if you compose two even permutations, you get an even permutation.

  • This Question is Closed
  1. watchmath
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    even+even=even

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    permutation formula nPr = n!/(n-r)! where n is total object taken, and r= objects taken at a time proof: nPr =n!/(n-r)! 2P2= 2!/(2-2)! = 2!/0! = 2 where 2 is even

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    therefore, if you compose two even permutation you'll always get an even answer

  4. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    try other given like 4P2 and you will also get an even answer.

  5. watchmath
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think what he meant by even permutation are the elements in permutation group that can be written as a product of even cycles.

  6. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry back, ye what watchmath said, logically it makes sense since you need a even number of transpositions to compose a even permutation, but i wasn't sure of the generic proof.

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.