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anonymous
 4 years ago
A university bookstore recently sold a wirebound graphpaper notebook for $1.10, and a collegeruled notebook for $3.16. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $102.38. How many of each type were sold?
anonymous
 4 years ago
A university bookstore recently sold a wirebound graphpaper notebook for $1.10, and a collegeruled notebook for $3.16. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $102.38. How many of each type were sold?

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.0w + c = 50 1.10w + 3.16c = 102.38 Solve the system

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Basically you write both equations in terms of w, set w = w, cross multiply, solve for c, then solve for w: w + c = 50 1.10w + 3.16c = 102.38 w = 50  c w = (102.38  3.16c)/1.10 w = w 1.10(50  c) = 102.38  3.16c 55  1.10c = 102.38  3.16c 1.10c + 3.16c = 102.38  55 2.06c = 47.38 c = 47.38/2.06 c = 23 Do you think you can find w?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so is that the answer

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0If you don't understand my steps, you should consider consulting a tutor.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well do I need to work this out as well w = (102.38  3.16c)/1.10

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You only needed to solve for c and w. You have both values now. c = 23, w = 27. The only thing you need to do is study and understand the steps I've given you.
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