anonymous
  • anonymous
Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7. y = x + 8 y = x - 4 y = x + 4 y = x - 8
Mathematics
jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
parallel lines have same homogenous parts and differ by the particular part
amistre64
  • amistre64
keep the x and lose the constant; then calibrate a new constant with the given point
amistre64
  • amistre64
y = x + 7 y = x + c ; use(6,-2) -2 = 6 + c -8 = c y = x-8

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anonymous
  • anonymous
y=ax+b if lines are parallel then they have the same ``a`` so y=x+7 a=1 y_2=1x+b if a point on a line then (6,-2)=(x,y) -2=1*6+b b=-8 y_2=x-8

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