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anonymous
 4 years ago
Can anyone do this??? The annual interest on a 19000 investment exceeds the interest earned on a 18000 investment by 204. the 19000 is invested at a .6% higher rater than the 18000. What is the interest rate of each investment?
anonymous
 4 years ago
Can anyone do this??? The annual interest on a 19000 investment exceeds the interest earned on a 18000 investment by 204. the 19000 is invested at a .6% higher rater than the 18000. What is the interest rate of each investment?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i messed this up somehow let me start again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. i'm quite confused

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah you should be because i was being stupid. let me start over

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0put the rate of the 18000 investment at r the rate of the 19000 investment is r+.006 we have to work with numbers, not percents

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then you know that the return on 18000 is \[18000\times r\] and the return on 19000 is \[19000\times (r+.006)\] and you know that the second one is $204 more than the first, so \[18000\times r +204=19000(r+.006)\] now we can solve for r

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[18000r+204=19000r + .006\times 19000\] \[18000r + 204=19000 r + 114\] \[204114=19000r 18000r\] \[90=1000r\] \[r=\frac{90}{1000}=\frac{9}{100}=9\%\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0love to know where they got 9% interest , i would go invest there

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to have the interest for both. do i add or subtract .6%
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