## anonymous 4 years ago Can anyone do this??? The annual interest on a 19000 investment exceeds the interest earned on a 18000 investment by 204. the 19000 is invested at a .6% higher rater than the 18000. What is the interest rate of each investment?

1. anonymous

i messed this up somehow let me start again

2. anonymous

ok. i'm quite confused

3. anonymous

yeah you should be because i was being stupid. let me start over

4. anonymous

ok

5. anonymous

put the rate of the 18000 investment at r the rate of the 19000 investment is r+.006 we have to work with numbers, not percents

6. anonymous

then you know that the return on 18000 is $18000\times r$ and the return on 19000 is $19000\times (r+.006)$ and you know that the second one is \$204 more than the first, so $18000\times r +204=19000(r+.006)$ now we can solve for r

7. anonymous

$18000r+204=19000r + .006\times 19000$ $18000r + 204=19000 r + 114$ $204-114=19000r -18000r$ $90=1000r$ $r=\frac{90}{1000}=\frac{9}{100}=9\%$

8. anonymous

love to know where they got 9% interest , i would go invest there

9. anonymous

i have to have the interest for both. do i add or subtract .6%

10. anonymous

?