A 425-g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,

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A 425-g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,

Physics
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Newton's Second Law: Force = Mass x Acceleration F = ma
i tried that and I got 36 550, but the answers provided are: 41 N [down], 32 N [u], 32 N [down], 37 N [up], and 41 N [up]?... btw, what is the general equation for this: y(t) = something involving initial velocity + something involving gravity.
You have to write the mass in kg, so m = 0.425 g. ===== \[ y(t) = vt - \frac{1}{2}gt^2 \] where v is the initial velocity

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oihhh, omg thank you!
****Correction, m = 0.425 kg, NOT g.
ohh.. thank you so much!!
so how does that relate to N [direction]?
It asks, "what is the value of the force BY the engine ON the rocket." Therefore, the force we are considering is acting on the rocket. Which direction does the rocket travel? The force must act in the same direction.

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