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anonymous
 4 years ago
A 425g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,
anonymous
 4 years ago
A 425g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Newton's Second Law: Force = Mass x Acceleration F = ma

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried that and I got 36 550, but the answers provided are: 41 N [down], 32 N [u], 32 N [down], 37 N [up], and 41 N [up]?... btw, what is the general equation for this: y(t) = something involving initial velocity + something involving gravity.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0You have to write the mass in kg, so m = 0.425 g. ===== \[ y(t) = vt  \frac{1}{2}gt^2 \] where v is the initial velocity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oihhh, omg thank you!

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0****Correction, m = 0.425 kg, NOT g.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh.. thank you so much!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so how does that relate to N [direction]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It asks, "what is the value of the force BY the engine ON the rocket." Therefore, the force we are considering is acting on the rocket. Which direction does the rocket travel? The force must act in the same direction.
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