anonymous
  • anonymous
A 425-g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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JamesJ
  • JamesJ
Newton's Second Law: Force = Mass x Acceleration F = ma
anonymous
  • anonymous
i tried that and I got 36 550, but the answers provided are: 41 N [down], 32 N [u], 32 N [down], 37 N [up], and 41 N [up]?... btw, what is the general equation for this: y(t) = something involving initial velocity + something involving gravity.
JamesJ
  • JamesJ
You have to write the mass in kg, so m = 0.425 g. ===== \[ y(t) = vt - \frac{1}{2}gt^2 \] where v is the initial velocity

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anonymous
  • anonymous
oihhh, omg thank you!
JamesJ
  • JamesJ
****Correction, m = 0.425 kg, NOT g.
anonymous
  • anonymous
ohh.. thank you so much!!
anonymous
  • anonymous
so how does that relate to N [direction]?
anonymous
  • anonymous
It asks, "what is the value of the force BY the engine ON the rocket." Therefore, the force we are considering is acting on the rocket. Which direction does the rocket travel? The force must act in the same direction.

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