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anonymous

  • 4 years ago

A 425-g model rocket is accelerated upward at 86 m/s^2 by its engine. What is the value of the force exerted by the engine on the rocket? a = 86 m/s^2, m = 425 g,

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  1. JamesJ
    • 4 years ago
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    Newton's Second Law: Force = Mass x Acceleration F = ma

  2. anonymous
    • 4 years ago
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    i tried that and I got 36 550, but the answers provided are: 41 N [down], 32 N [u], 32 N [down], 37 N [up], and 41 N [up]?... btw, what is the general equation for this: y(t) = something involving initial velocity + something involving gravity.

  3. JamesJ
    • 4 years ago
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    You have to write the mass in kg, so m = 0.425 g. ===== \[ y(t) = vt - \frac{1}{2}gt^2 \] where v is the initial velocity

  4. anonymous
    • 4 years ago
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    oihhh, omg thank you!

  5. JamesJ
    • 4 years ago
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    ****Correction, m = 0.425 kg, NOT g.

  6. anonymous
    • 4 years ago
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    ohh.. thank you so much!!

  7. anonymous
    • 4 years ago
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    so how does that relate to N [direction]?

  8. anonymous
    • 4 years ago
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    It asks, "what is the value of the force BY the engine ON the rocket." Therefore, the force we are considering is acting on the rocket. Which direction does the rocket travel? The force must act in the same direction.

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