A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
PLEASE HELP!! > A balloon rises at a rate of 4 meters per second from a point on the ground 40 meters from an observer. What is the rate of change of the angle of elevation (in rad/sec) when the balloon is 40 meters above the ground?
anonymous
 4 years ago
PLEASE HELP!! > A balloon rises at a rate of 4 meters per second from a point on the ground 40 meters from an observer. What is the rate of change of the angle of elevation (in rad/sec) when the balloon is 40 meters above the ground?

This Question is Closed

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Step 1: draw a diagram. If you done that, tell us what an expression for angle of elevation, call it A in terms of 40 meters and the balloon's height, h. And what is height h as a function of time t?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0When the balloon is h meters off the ground, what is the trigonometric expression for the angle of elevation. It involves something like sin or cos or tan or cot or sec or cosec.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0The horizontal distance of 40 m and the vertical height of h, form two sides of rightangled triangle. The observer is sitting at the end of the horizontal 40 m looking up at the balloon. The angle at which she's looking is the angle of elevation, call it A. What is the trig relationship between that angle, h and 40?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0That is, she's looking along the diagonal towards the balloon.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0I'm still waiting for an equation in which A appears.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0tan A = h/40 That's the equation.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Now, the height h = 4t, because it's rising at a constant velocity. Hence tan A = 4t/40 = t/10 or A = arctan(t/10). The question now asks you for dA/dt when the balloon is 40 meters off the ground. So you need to a) calculate dA/dt in general b) find the value of t for which h = 40 m c) evaluate dA/dt for that value of t.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.