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moneysotrue
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Given: f'(x)=4x^3+4x+6. How many points of inflection will the graph of f(x) have?
 2 years ago
 2 years ago
moneysotrue Group Title
Given: f'(x)=4x^3+4x+6. How many points of inflection will the graph of f(x) have?
 2 years ago
 2 years ago

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Denebel Group TitleBest ResponseYou've already chosen the best response.1
Find the second derivative... find the derivative of this (since this equation is already the first derivative) and set it equal to 0.. that will be where your point(s) of inflection will be.
 2 years ago

moneysotrue Group TitleBest ResponseYou've already chosen the best response.0
for my second derivative i got f"(x)=12x^2+4 but I dont think there will be any points am I correct?
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
If you set your second derivative equal to 0, you will get a point.
 2 years ago

moneysotrue Group TitleBest ResponseYou've already chosen the best response.0
Should I use the quadratic formula?
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Second derivative = 12x + 4 = 0 12x = 4 x=  1/3
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
So you will have 1 point of inflection. You can check this by integrating the first derivative to find the original function. f(x) would be x^4 + 2x + 6x. Graph this and you will see there is one point of inflection.
 2 years ago

moneysotrue Group TitleBest ResponseYou've already chosen the best response.0
No the second derivative would be 12\[x^2\]+4
 2 years ago

moneysotrue Group TitleBest ResponseYou've already chosen the best response.0
b/c arent I suppose to subtract 1 from my exponent? each time I take my derivative
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Oops, yes. Oh I see now. I would say no points of inflection
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
12x^2 + 4 = 0 x^2 = 1/3 but squares of numbers cannot be negatives
 2 years ago

moneysotrue Group TitleBest ResponseYou've already chosen the best response.0
okay thanks! I appreciate the help.
 2 years ago
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