Ok, I need help figuring out, (-7 + sqrt-5) ^2. I know it's re-written as (-7 + sqrt -5) (-7 + sqrt -5). Do I use FOIL to figure this out?

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Ok, I need help figuring out, (-7 + sqrt-5) ^2. I know it's re-written as (-7 + sqrt -5) (-7 + sqrt -5). Do I use FOIL to figure this out?

Mathematics
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FOIL would be an excellent strategy in this case.
Yes, but rewrite it. sqrt -5 means imaginary..
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how do I rewrite it? I think that's the part that's stumping me
oh wait, Cinar already did. Thanks! so sqrt -5 equals sq root 5i?
The equation you have is the following correct?\[(-7 + \sqrt{-5})^2\]
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@kinggeorge: Yes, that is correct! how did you get the square root symbo??
If you go into the equation editor on the bottom left of the comment box. For example, you can type "sqrt{-5}" without the quotes to get \[\sqrt{-5}\]It takes some getting used to, but is very clear. Moving on, since that is the equation, cinar's solution is correct.
I know it's the imaginary units that are throwing me off
As for imaginary units, the square root of negative one is defined as the letter i. Or, \[\begin{matrix} \sqrt{-1} = i \\ i^2 = -1 \end{matrix}\]So if you have a radical such as \[\sqrt{-20}\] you can simplify and solve like so\[\sqrt{-20} = \sqrt{(-1) \cdot 4 \cdot 5} = \sqrt{-1} \cdot \sqrt{4} \cdot \sqrt{5} = 2i \sqrt{5}\]
wow, this is great!! thank you so much. It's making a lot more sense to me now!
you're very welcome

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