anonymous
  • anonymous
Ok, I need help figuring out, (-7 + sqrt-5) ^2. I know it's re-written as (-7 + sqrt -5) (-7 + sqrt -5). Do I use FOIL to figure this out?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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KingGeorge
  • KingGeorge
FOIL would be an excellent strategy in this case.
anonymous
  • anonymous
Yes, but rewrite it. sqrt -5 means imaginary..
anonymous
  • anonymous
|dw:1327303757412:dw|

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anonymous
  • anonymous
how do I rewrite it? I think that's the part that's stumping me
anonymous
  • anonymous
oh wait, Cinar already did. Thanks! so sqrt -5 equals sq root 5i?
KingGeorge
  • KingGeorge
The equation you have is the following correct?\[(-7 + \sqrt{-5})^2\]
anonymous
  • anonymous
|dw:1327303914040:dw|
anonymous
  • anonymous
@kinggeorge: Yes, that is correct! how did you get the square root symbo??
KingGeorge
  • KingGeorge
If you go into the equation editor on the bottom left of the comment box. For example, you can type "sqrt{-5}" without the quotes to get \[\sqrt{-5}\]It takes some getting used to, but is very clear. Moving on, since that is the equation, cinar's solution is correct.
anonymous
  • anonymous
I know it's the imaginary units that are throwing me off
KingGeorge
  • KingGeorge
As for imaginary units, the square root of negative one is defined as the letter i. Or, \[\begin{matrix} \sqrt{-1} = i \\ i^2 = -1 \end{matrix}\]So if you have a radical such as \[\sqrt{-20}\] you can simplify and solve like so\[\sqrt{-20} = \sqrt{(-1) \cdot 4 \cdot 5} = \sqrt{-1} \cdot \sqrt{4} \cdot \sqrt{5} = 2i \sqrt{5}\]
anonymous
  • anonymous
wow, this is great!! thank you so much. It's making a lot more sense to me now!
KingGeorge
  • KingGeorge
you're very welcome

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