## anonymous 4 years ago 11mL of 1 mol/L NaCl and 8mL of 0.10 mol/L AgNO3 they react. Find theoretical yield.

1. anonymous

Can you figure out the balanced equation?

2. anonymous

i did NaCl = AgNO3 -> NaNO3 + AgCl

3. anonymous

NaCl + *

4. anonymous

that's balanced^

5. anonymous

alright now you have to find the limiting reagent can you do that?

6. anonymous

i did i got AgNO3 as the limiting

7. anonymous

now how do i get the theoretical yield if the mole ratio is 1:1

8. anonymous

Does it tell you what product to take it to? if not pick one

9. anonymous

no its one of those questions where you just have to find theoretical yield :O

10. anonymous

$8 ml AgNO_3(\frac{0.10 mole AgNO_3}{1000 ml AgNO_3})(\frac{1 mole AgCl}{1 mole AgNO_3})(\frac{MM AgCl}{1 mole AgCl})=theoridcal yeild$ where i put in MM put the molar mass of AGCL and follow the steps and this should tell you the theoridical yeild