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anonymous

  • 4 years ago

11mL of 1 mol/L NaCl and 8mL of 0.10 mol/L AgNO3 they react. Find theoretical yield.

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  1. anonymous
    • 4 years ago
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    Can you figure out the balanced equation?

  2. anonymous
    • 4 years ago
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    i did NaCl = AgNO3 -> NaNO3 + AgCl

  3. anonymous
    • 4 years ago
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    NaCl + *

  4. anonymous
    • 4 years ago
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    that's balanced^

  5. anonymous
    • 4 years ago
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    alright now you have to find the limiting reagent can you do that?

  6. anonymous
    • 4 years ago
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    i did i got AgNO3 as the limiting

  7. anonymous
    • 4 years ago
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    now how do i get the theoretical yield if the mole ratio is 1:1

  8. anonymous
    • 4 years ago
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    Does it tell you what product to take it to? if not pick one

  9. anonymous
    • 4 years ago
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    no its one of those questions where you just have to find theoretical yield :O

  10. anonymous
    • 4 years ago
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    \[8 ml AgNO_3(\frac{0.10 mole AgNO_3}{1000 ml AgNO_3})(\frac{1 mole AgCl}{1 mole AgNO_3})(\frac{MM AgCl}{1 mole AgCl})=theoridcal yeild\] where i put in MM put the molar mass of AGCL and follow the steps and this should tell you the theoridical yeild

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