anonymous
  • anonymous
11mL of 1 mol/L NaCl and 8mL of 0.10 mol/L AgNO3 they react. Find theoretical yield.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Can you figure out the balanced equation?
anonymous
  • anonymous
i did NaCl = AgNO3 -> NaNO3 + AgCl
anonymous
  • anonymous
NaCl + *

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anonymous
  • anonymous
that's balanced^
anonymous
  • anonymous
alright now you have to find the limiting reagent can you do that?
anonymous
  • anonymous
i did i got AgNO3 as the limiting
anonymous
  • anonymous
now how do i get the theoretical yield if the mole ratio is 1:1
anonymous
  • anonymous
Does it tell you what product to take it to? if not pick one
anonymous
  • anonymous
no its one of those questions where you just have to find theoretical yield :O
anonymous
  • anonymous
\[8 ml AgNO_3(\frac{0.10 mole AgNO_3}{1000 ml AgNO_3})(\frac{1 mole AgCl}{1 mole AgNO_3})(\frac{MM AgCl}{1 mole AgCl})=theoridcal yeild\] where i put in MM put the molar mass of AGCL and follow the steps and this should tell you the theoridical yeild

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