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## anonymous 4 years ago How do I solve for x if I have x^(-5/2)=(8/3)?

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1. KingGeorge

${x^{-{5 \over 2}}} = {{1 \over x^{5 \over 2}}} = {1 \over \sqrt{x^5}} = {8 \over 3}$so$\sqrt{x^5} = {3 \over 8} \longrightarrow {x^5}= {9 \over 64}$so$x = \sqrt[5]{9 \over 64}$

2. anonymous

Thanks!

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