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anonymous

  • 5 years ago

Factor if possible : 6x^2-2xy-8y^2

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  1. anonymous
    • 5 years ago
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    2 (3 x-4 y) (x+y)

  2. anonymous
    • 5 years ago
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    Use http://www.wolframalpha.com if you continue to have more of these factoring questions. Simply type the function follow by factor. Such as 6x^2-2xy-8y^2 factor. 2 (3 x-4 y) (x+y) is the solution

  3. anonymous
    • 5 years ago
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    First observe that 2 is a common factor;factor it out you get : \[2(3x^2 - xy - 4y^2)\] Further observe that the square variables form the product in between when their square root is taken, thus we take the extremes and put them together with a single degree as such : \[(3x - 4y)\] Then we multiply this by (x+y);plus because we have two negative terms. We put them together and we have our answer!

  4. anonymous
    • 5 years ago
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    Thank you Snakefangs, and Aron.

  5. anonymous
    • 5 years ago
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    Welcome.

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