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anonymous
 4 years ago
[(e^x)(1)(x)]/ (x^2) as lim x > 0
anonymous
 4 years ago
[(e^x)(1)(x)]/ (x^2) as lim x > 0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Again apply L' Hospital's Rule to get 1/2 as the limit.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0expand e^x and see it fall all in place ans is 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cant get the answer but i believe you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how exactly did u expand e to x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The given limit is in its indeterminate form thus we differentiate the numerator and denominator to get 1/2[(e^x  1)/x] now the limit of [e^x  1/]x is nothing but 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0e^x is expanded by using the Taylor Series.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That is euler series not Taylor

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i didnt know you can just differentiate the numerator and the denominator while the numerator was being subtracted from e^x  1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is actually Maclaurin series which is a special case of Taylor Series.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you want you can actually prove it using cauchy mean valuue theorem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can someone quickly show me how you get the answer to my other problem under this? thank you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0WHere is the other problem
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