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1.how can i understand how acceleration and displacemenyt varies from a displacement time graph??

srry accleration and velocity i meant

based on that tell me hw the sign in varous intervals OA ,,AB ,BC and CD is -, 0 ,+ ,0

|dw:1327309166279:dw|

i mean sign of acceleration

eashmore i asked how we can evaluate from the graph

look the graph

2.|dw:1327309473228:dw|

here its a smooth in clined planethe time taken to reach bttom is sqr(2l/g)

i dont understand why we can use s=1/2gt^2 directly here

ipls help

but the answer is sqr(2l/g)

we just applied equaion of motion just as usual why??

|dw:1327309719031:dw|

it is said that acceleration of A and B are in ratio tan 60 to tan 30 how????

helo pls help

Patience....

k

are u sure?/

If that is a displacement vs. time graph, and lines A and B are straight, then yes, I'm 100% sure.

y is a=0??

I told you why. Because the second derivative of a straight line is zero.

k tel me the othr one

yea i agree with that t=sqrt(2l/g sin theta)

but it is not there in options

hey i got the answer but there is no arc sin theta

\[\arcsin(\theta) = {1 \over \sin(\theta)}\]

lol

k i got it ithought it was sin inverse

\[\arcsin(\theta) = {1 \over \sin(\theta)} = \sin^{-1}(\theta)\]

hey thts not

1/sin theta is cosec theta

Yeah. You're right.

Just pretend like it is here.

:)