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anonymous

  • 4 years ago

What is the slope for the 1st four seconds of the journey. see attached graph.

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  1. anonymous
    • 4 years ago
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  2. anonymous
    • 4 years ago
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    sorry??

  3. anonymous
    • 4 years ago
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    I am not familiar with trigonometry

  4. anonymous
    • 4 years ago
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    leave all....slope is 2....thats it...

  5. anonymous
    • 4 years ago
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    how??

  6. anonymous
    • 4 years ago
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    y/x is slope... for 0 to 4 sec y=8 and x=4...so y/x=2

  7. anonymous
    • 4 years ago
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    why teacher insisted we use the formula (x2-x) (y2-y)

  8. anonymous
    • 4 years ago
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    leave all formulas...the best method it y/x....

  9. anonymous
    • 4 years ago
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    I dont understand now y =8

  10. anonymous
    • 4 years ago
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    why is y not 4

  11. anonymous
    • 4 years ago
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    coz the line is starting from -4.... actually y means y2-y1....and x means x2-x1.....

  12. anonymous
    • 4 years ago
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    one point on the graph is (4, 4) another is (2,0) you can use \[\frac{4-0}{4-2}=\frac{4}{2}=2\] if you like

  13. phi
    • 4 years ago
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    You said "why teacher insisted we use the formula (x2-x) (y2-y)" look at your notes more carefully. The teacher said use \[ slope= \frac{y_2 - y_1}{x_2 - x_1} \] where you have 2 points on the line: point1= \( (x_1,y_1) \) point2= \( (x_2,y_2) \) Can you find 2 points on the line that starts at t=0 and ends at t=4 ? It looks like at t=0 d= -4, so in point format that is (0, -4) At t= 4, it looks like d= +4, so another point is (4,4) See Sat's post above on how to use the slope formula to get the answer

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