What is the slope for the 1st four seconds of the journey. see attached graph.

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What is the slope for the 1st four seconds of the journey. see attached graph.

Mathematics
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1 Attachment
sorry??
I am not familiar with trigonometry

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leave all....slope is 2....thats it...
how??
y/x is slope... for 0 to 4 sec y=8 and x=4...so y/x=2
why teacher insisted we use the formula (x2-x) (y2-y)
leave all formulas...the best method it y/x....
I dont understand now y =8
why is y not 4
coz the line is starting from -4.... actually y means y2-y1....and x means x2-x1.....
one point on the graph is (4, 4) another is (2,0) you can use \[\frac{4-0}{4-2}=\frac{4}{2}=2\] if you like
  • phi
You said "why teacher insisted we use the formula (x2-x) (y2-y)" look at your notes more carefully. The teacher said use \[ slope= \frac{y_2 - y_1}{x_2 - x_1} \] where you have 2 points on the line: point1= \( (x_1,y_1) \) point2= \( (x_2,y_2) \) Can you find 2 points on the line that starts at t=0 and ends at t=4 ? It looks like at t=0 d= -4, so in point format that is (0, -4) At t= 4, it looks like d= +4, so another point is (4,4) See Sat's post above on how to use the slope formula to get the answer

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