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anonymous
 4 years ago
What is the slope for the 1st four seconds of the journey. see attached graph.
anonymous
 4 years ago
What is the slope for the 1st four seconds of the journey. see attached graph.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am not familiar with trigonometry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0leave all....slope is 2....thats it...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y/x is slope... for 0 to 4 sec y=8 and x=4...so y/x=2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why teacher insisted we use the formula (x2x) (y2y)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0leave all formulas...the best method it y/x....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont understand now y =8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0coz the line is starting from 4.... actually y means y2y1....and x means x2x1.....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one point on the graph is (4, 4) another is (2,0) you can use \[\frac{40}{42}=\frac{4}{2}=2\] if you like

phi
 4 years ago
Best ResponseYou've already chosen the best response.0You said "why teacher insisted we use the formula (x2x) (y2y)" look at your notes more carefully. The teacher said use \[ slope= \frac{y_2  y_1}{x_2  x_1} \] where you have 2 points on the line: point1= \( (x_1,y_1) \) point2= \( (x_2,y_2) \) Can you find 2 points on the line that starts at t=0 and ends at t=4 ? It looks like at t=0 d= 4, so in point format that is (0, 4) At t= 4, it looks like d= +4, so another point is (4,4) See Sat's post above on how to use the slope formula to get the answer
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