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## anonymous 4 years ago What is the slope for the 1st four seconds of the journey. see attached graph.

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1. anonymous

2. anonymous

sorry??

3. anonymous

I am not familiar with trigonometry

4. anonymous

leave all....slope is 2....thats it...

5. anonymous

how??

6. anonymous

y/x is slope... for 0 to 4 sec y=8 and x=4...so y/x=2

7. anonymous

why teacher insisted we use the formula (x2-x) (y2-y)

8. anonymous

leave all formulas...the best method it y/x....

9. anonymous

I dont understand now y =8

10. anonymous

why is y not 4

11. anonymous

coz the line is starting from -4.... actually y means y2-y1....and x means x2-x1.....

12. anonymous

one point on the graph is (4, 4) another is (2,0) you can use $\frac{4-0}{4-2}=\frac{4}{2}=2$ if you like

13. phi

You said "why teacher insisted we use the formula (x2-x) (y2-y)" look at your notes more carefully. The teacher said use $slope= \frac{y_2 - y_1}{x_2 - x_1}$ where you have 2 points on the line: point1= $$(x_1,y_1)$$ point2= $$(x_2,y_2)$$ Can you find 2 points on the line that starts at t=0 and ends at t=4 ? It looks like at t=0 d= -4, so in point format that is (0, -4) At t= 4, it looks like d= +4, so another point is (4,4) See Sat's post above on how to use the slope formula to get the answer

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