anonymous
  • anonymous
Could someone please solve and explain the following problem? 5x^2 + 1 = 37 Thanks!
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
plus minus 6 divided by the square root of 5.
anonymous
  • anonymous
Use Quadratic formula, you will get \( \large \left\{\left\{x= -\frac{6}{\sqrt{5}}\right\},\left\{x = \frac{6}{\sqrt{5}}\right\}\right\} \)
anonymous
  • anonymous
Here are the steps.... 5x^2 + 1 - 37 = 0 implies 5x^2 - 36 = 0 implies 5x^2 = 36 implies x^2 = 36/5 implies x = plus minus 6/root 5

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Ok, that was my answer too. The textbook said it was 6 times the root of 5 over 5...
anonymous
  • anonymous
W\[6\sqrt{5}/5 * \sqrt{5}/\sqrt{5} = 6*5/5\sqrt{5} = 6/\sqrt{5}\]
anonymous
  • anonymous
^^ ohhhhh ok. i'm just glad i know i wasn't missing some really big step. xD thanks for you help!
anonymous
  • anonymous
Welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.