anonymous
  • anonymous
Please solve and explain? "A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 600 square meters, what is the width of the path?"
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
whats the area of the pool?
amistre64
  • amistre64
im assuming a rectanglular pool
anonymous
  • anonymous
i'm guessing since the pool is 10 by 20, the area would be 200 maybe?? :/

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More answers

amistre64
  • amistre64
correct, and since the total area involoved is 600, all we gotta do is subtract the pool from it to get the path
amistre64
  • amistre64
(10+x)(20+x) = 600 sorry read the question wrong :)
amistre64
  • amistre64
ugh, let me draw lol
anonymous
  • anonymous
Haha ok thanks!! :D
amistre64
  • amistre64
|dw:1327323653837:dw|
amistre64
  • amistre64
thats better :) sooooo, (10+x+x)(20+x+x)= 600
amistre64
  • amistre64
10+2x 20+2x ------ 200 +40x +20x +4x^2 --------------- 200 +60x +4x^2 = 600 -600 -600 --------------------- -400 +60x +4x^2 = 0 /4 /4 /4 ---------------- -100 +15x+x^2 = 0 is our quadratic to solve
anonymous
  • anonymous
:o omg you just totally drew the picture that was in my text book! awesome!! :D how did you know to add the xs to the 10 and 20? \
amistre64
  • amistre64
x is teh standard variable to use; and since the path is the same width all the way around you just add find the overall width and length with is just 2x more than the pools
amistre64
  • amistre64
in other words, the path is so many units wide; and that width is added to each end of the pool
anonymous
  • anonymous
amazing!! thank you so much! :D now i would just use the quadratic formula to solve the equation, right?
amistre64
  • amistre64
yep
amistre64
  • amistre64
i wonder, since the are of the path is 600-200 = 400 and the path itself creates a square; that each side is then sqrt(400) and since that is double the width we divide that in half: sqrt(400)/2 maybe
amistre64
  • amistre64
|dw:1327324075871:dw|
amistre64
  • amistre64
nah, thats a bad idea :) almost good, but really bad. use the quad formula
anonymous
  • anonymous
haha ok! thanks for all your help! you're really smart lol :D
amistre64
  • amistre64
i have my moments :) good luck

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