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whats the area of the pool?
im assuming a rectanglular pool
i'm guessing since the pool is 10 by 20, the area would be 200 maybe?? :/
correct, and since the total area involoved is 600, all we gotta do is subtract the pool from it to get the path
(10+x)(20+x) = 600 sorry read the question wrong :)
ugh, let me draw lol
Haha ok thanks!! :D
thats better :) sooooo, (10+x+x)(20+x+x)= 600
10+2x 20+2x ------ 200 +40x +20x +4x^2 --------------- 200 +60x +4x^2 = 600 -600 -600 --------------------- -400 +60x +4x^2 = 0 /4 /4 /4 ---------------- -100 +15x+x^2 = 0 is our quadratic to solve
:o omg you just totally drew the picture that was in my text book! awesome!! :D how did you know to add the xs to the 10 and 20? \
x is teh standard variable to use; and since the path is the same width all the way around you just add find the overall width and length with is just 2x more than the pools
in other words, the path is so many units wide; and that width is added to each end of the pool
amazing!! thank you so much! :D now i would just use the quadratic formula to solve the equation, right?
i wonder, since the are of the path is 600-200 = 400 and the path itself creates a square; that each side is then sqrt(400) and since that is double the width we divide that in half: sqrt(400)/2 maybe
nah, thats a bad idea :) almost good, but really bad. use the quad formula
haha ok! thanks for all your help! you're really smart lol :D
i have my moments :) good luck