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anonymous
 4 years ago
Please solve and explain? "A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 600 square meters, what is the width of the path?"
anonymous
 4 years ago
Please solve and explain? "A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 600 square meters, what is the width of the path?"

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1whats the area of the pool?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1im assuming a rectanglular pool

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'm guessing since the pool is 10 by 20, the area would be 200 maybe?? :/

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1correct, and since the total area involoved is 600, all we gotta do is subtract the pool from it to get the path

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1(10+x)(20+x) = 600 sorry read the question wrong :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327323653837:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1thats better :) sooooo, (10+x+x)(20+x+x)= 600

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.110+2x 20+2x  200 +40x +20x +4x^2  200 +60x +4x^2 = 600 600 600  400 +60x +4x^2 = 0 /4 /4 /4  100 +15x+x^2 = 0 is our quadratic to solve

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:o omg you just totally drew the picture that was in my text book! awesome!! :D how did you know to add the xs to the 10 and 20? \

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1x is teh standard variable to use; and since the path is the same width all the way around you just add find the overall width and length with is just 2x more than the pools

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1in other words, the path is so many units wide; and that width is added to each end of the pool

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0amazing!! thank you so much! :D now i would just use the quadratic formula to solve the equation, right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i wonder, since the are of the path is 600200 = 400 and the path itself creates a square; that each side is then sqrt(400) and since that is double the width we divide that in half: sqrt(400)/2 maybe

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327324075871:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1nah, thats a bad idea :) almost good, but really bad. use the quad formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha ok! thanks for all your help! you're really smart lol :D

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i have my moments :) good luck
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