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anonymous

  • 4 years ago

Please solve and explain? "A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 600 square meters, what is the width of the path?"

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  1. amistre64
    • 4 years ago
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    whats the area of the pool?

  2. amistre64
    • 4 years ago
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    im assuming a rectanglular pool

  3. anonymous
    • 4 years ago
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    i'm guessing since the pool is 10 by 20, the area would be 200 maybe?? :/

  4. amistre64
    • 4 years ago
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    correct, and since the total area involoved is 600, all we gotta do is subtract the pool from it to get the path

  5. amistre64
    • 4 years ago
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    (10+x)(20+x) = 600 sorry read the question wrong :)

  6. amistre64
    • 4 years ago
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    ugh, let me draw lol

  7. anonymous
    • 4 years ago
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    Haha ok thanks!! :D

  8. amistre64
    • 4 years ago
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    |dw:1327323653837:dw|

  9. amistre64
    • 4 years ago
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    thats better :) sooooo, (10+x+x)(20+x+x)= 600

  10. amistre64
    • 4 years ago
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    10+2x 20+2x ------ 200 +40x +20x +4x^2 --------------- 200 +60x +4x^2 = 600 -600 -600 --------------------- -400 +60x +4x^2 = 0 /4 /4 /4 ---------------- -100 +15x+x^2 = 0 is our quadratic to solve

  11. anonymous
    • 4 years ago
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    :o omg you just totally drew the picture that was in my text book! awesome!! :D how did you know to add the xs to the 10 and 20? \

  12. amistre64
    • 4 years ago
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    x is teh standard variable to use; and since the path is the same width all the way around you just add find the overall width and length with is just 2x more than the pools

  13. amistre64
    • 4 years ago
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    in other words, the path is so many units wide; and that width is added to each end of the pool

  14. anonymous
    • 4 years ago
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    amazing!! thank you so much! :D now i would just use the quadratic formula to solve the equation, right?

  15. amistre64
    • 4 years ago
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    yep

  16. amistre64
    • 4 years ago
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    i wonder, since the are of the path is 600-200 = 400 and the path itself creates a square; that each side is then sqrt(400) and since that is double the width we divide that in half: sqrt(400)/2 maybe

  17. amistre64
    • 4 years ago
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    |dw:1327324075871:dw|

  18. amistre64
    • 4 years ago
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    nah, thats a bad idea :) almost good, but really bad. use the quad formula

  19. anonymous
    • 4 years ago
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    haha ok! thanks for all your help! you're really smart lol :D

  20. amistre64
    • 4 years ago
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    i have my moments :) good luck

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