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moongazer

  • 4 years ago

Teach me in solving this inequality.

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  1. moongazer
    • 4 years ago
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    |2x−11|−2>4x+7

  2. moongazer
    • 4 years ago
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    I know how to solve equations. But I just don't know how to solve if it has absolute value sign. Teach me please. :)

  3. anonymous
    • 4 years ago
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    x < 1/3

  4. moongazer
    • 4 years ago
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    how?

  5. moongazer
    • 4 years ago
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    Teach me please and give me another example after teaching it. so that I can practice. and you will going to check it if I am right.

  6. anonymous
    • 4 years ago
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    To remove the modulus sign we write \[|2x -11|\] as \[\sqrt{2x - 11}^2\]

  7. moongazer
    • 4 years ago
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    Why is that?

  8. vishal_kothari
    • 4 years ago
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    http://www.mathmotivation.com/lectures/Inequalities.pdf

  9. anonymous
    • 4 years ago
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    To remove any modulus sign write \[\left| ax + b \right| = (\sqrt{ax + b})^2\]

  10. moongazer
    • 4 years ago
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    Could you solve it step by step? and what is the reason behind To remove any modulus sign write

  11. moongazer
    • 4 years ago
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    \[\left| ax + b \right| = (\sqrt{ax + b})^2\]

  12. hoblos
    • 4 years ago
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    |2x−11|−2>4x+7 |2x−11| > 4x +9 then 2x-11 > 4x +9 OR 2x-11 < -(4x+9) -2x > 20 2x -11 < -4x -9 x<-10 6x < 2 x<1/3

  13. moongazer
    • 4 years ago
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    please explain

  14. hoblos
    • 4 years ago
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    rules: if |x| < a then -a<x<a if |x| >a then x>a OR x<-a

  15. hoblos
    • 4 years ago
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    you apply the second rule here

  16. moongazer
    • 4 years ago
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    Thanks!

  17. moongazer
    • 4 years ago
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    What if it is "="

  18. hoblos
    • 4 years ago
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    if |x| = a then x=a OR x=-a

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