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moongazer
 4 years ago
Teach me in solving this inequality.
moongazer
 4 years ago
Teach me in solving this inequality.

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moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0I know how to solve equations. But I just don't know how to solve if it has absolute value sign. Teach me please. :)

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0Teach me please and give me another example after teaching it. so that I can practice. and you will going to check it if I am right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0To remove the modulus sign we write \[2x 11\] as \[\sqrt{2x  11}^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0To remove any modulus sign write \[\left ax + b \right = (\sqrt{ax + b})^2\]

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0Could you solve it step by step? and what is the reason behind To remove any modulus sign write

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left ax + b \right = (\sqrt{ax + b})^2\]

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.22x−11−2>4x+7 2x−11 > 4x +9 then 2x11 > 4x +9 OR 2x11 < (4x+9) 2x > 20 2x 11 < 4x 9 x<10 6x < 2 x<1/3

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.2rules: if x < a then a<x<a if x >a then x>a OR x<a

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.2you apply the second rule here

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.2if x = a then x=a OR x=a
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