anonymous
  • anonymous
how to find the equation of diameter..? of a circle..whose equation is x2+Y2-12x+4Y+6=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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razor99
  • razor99
could u explain it clearly
anonymous
  • anonymous
You need to complete the square for both the x and y values within the equation.
anonymous
  • anonymous
mark..we have to find the equation of diameter?

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anonymous
  • anonymous
can anyof u tell me how to find the equation of diameter?
anonymous
  • anonymous
You need to put the equation in standard form first. \[x^2+y^2-12x+4y+6=0\] \[x^2-12x+y^2+4y+6=0\] \[(x^2-12x)+(y^2+4y)+6=0\] \[(x^2-12x +36-36)^2+(y^2+4y+4-4)+6=0\] this is the completing the square part \[(x^2-12x +36)^2-36+(y^2+4y+4)-4+6=0\] \[(x^2-12x +36)^2+(y^2+4y+4)+38=0\] \[(x-6)^2+(y+2)^2+38=0\]
anonymous
  • anonymous
oops, thte +38 should be -34
anonymous
  • anonymous
Once you move the -34 over, it means the radius is sqrt(34)
razor99
  • razor99
okay here is the formulae for the diameter
razor99
  • razor99
hey is it area or perimeter
anonymous
  • anonymous
its diameter of circle
anonymous
  • anonymous
yeah so the diameter is 2x the square root of 34
razor99
  • razor99
okay formulae of a diameter d=2xr
anonymous
  • anonymous
but we hav to find the equation not only diameter
razor99
  • razor99
oh first we have to slove it right
anonymous
  • anonymous
hmm..yup
anonymous
  • anonymous
hey razor r u on fb?
razor99
  • razor99
yeah
anonymous
  • anonymous
wud u lyk 2 b mah frnd..?
razor99
  • razor99
okay but i am a boy
anonymous
  • anonymous
uhh..y r u tellng mee lolz..!! it dsnt seem scary 2 mee
razor99
  • razor99
oh lets talk some other time okay u have a equation to do
anonymous
  • anonymous
yea..i got it
razor99
  • razor99
dont worry jimmyrep is coming
anonymous
  • anonymous
whoz he?
razor99
  • razor99
comeon u would know
razor99
  • razor99
Equation x2+Y2-12*x+4*Y+6=0 solved for x x = (Y2+4*Y+x2+6)/12
razor99
  • razor99
so the answer is
razor99
  • razor99
Equation x2+Y2-12*x+4*Y+6=0 solved for x x = (Y2+4*Y+x2+6)/12

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