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anonymous

  • 5 years ago

A particle of mass m fall freely from rest under gravity for a time 1/2k.how find the distance it has fallen and the speed attained.

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  1. ash2326
    • 5 years ago
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    s=ut+1/2 at^2 u is the initial velocity t a= acceleration here it's gravity t=time s=1/2* 9.8*t^2 substitute t to find the distance covered

  2. ash2326
    • 5 years ago
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    for speed v=u+at u=0 v is the final velocity v=9.8*t substitute t to find the velocity

  3. anonymous
    • 5 years ago
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    s=g/8k2 and v=g/2k isn't?

  4. ash2326
    • 5 years ago
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    yeah

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