anonymous
  • anonymous
A particle of mass m fall freely from rest under gravity for a time 1/2k.how find the distance it has fallen and the speed attained.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ash2326
  • ash2326
s=ut+1/2 at^2 u is the initial velocity t a= acceleration here it's gravity t=time s=1/2* 9.8*t^2 substitute t to find the distance covered
ash2326
  • ash2326
for speed v=u+at u=0 v is the final velocity v=9.8*t substitute t to find the velocity
anonymous
  • anonymous
s=g/8k2 and v=g/2k isn't?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ash2326
  • ash2326
yeah

Looking for something else?

Not the answer you are looking for? Search for more explanations.