A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
how does sum sin(pi/n) n>infinity diverge?
anonymous
 5 years ago
how does sum sin(pi/n) n>infinity diverge?

This Question is Closed

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.1For small \( x \) \[ \sin x \approx x \] Hence intuitively at least, \[ \sum_n \sin(\pi/n) \approx \sum_n \pi/n \] and that second sum diverges. Now that's not a proof, but it does suggest something. Try and bound \[ \sin(\pi/n) \] below by something that does diverge also.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that was my patter of thought, but doesn't that only work when x>0 not infinity?

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.1As n > infty, 1/n > 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does make sense sort of. thanks!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.