What are the possible number of positive, negative, and complex zeros of f(x) = 3x^4 – 5x^3 – x^2 – 8x + 4 ? Answer: A)Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 B)Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 C)Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 D)Positive: 3 or 1; Negative: 1; Complex: 2 or 0 help pleeeease:)

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What are the possible number of positive, negative, and complex zeros of f(x) = 3x^4 – 5x^3 – x^2 – 8x + 4 ? Answer: A)Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 B)Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 C)Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 D)Positive: 3 or 1; Negative: 1; Complex: 2 or 0 help pleeeease:)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I think it's C
The number of positive real zeros is equal to the number of sign changes or is less than that by an even number. There are two sign changes. So the positive roots would be 2 or 0 The number of negative real zeros is equal to the number of sign changes in f(-x) so find that first.
f(-x)=3x^4+5x^3-x^2+8x+4 So 2 sign changes implies 2 or 0 negative roots

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So far, it's C :D
mertsj, how can you tell if it's A or C?
It's not A because that does not allow for the possibility that there are 0 complex roots. If there are 2 positive and 2 negative (possibly) then there would be 0 complex since it has at most 4 roots.
so it's c:)
yes

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