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anonymous

  • 4 years ago

I need help again.... I will post the image in a bit

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  1. anonymous
    • 4 years ago
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    i am confused

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  2. ash2326
    • 4 years ago
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    we have \[ (x-3)(x+3)/x(x-5) * -x.(x-5)/(x^2-x-12). (x^2-8x+16)/(x-4)\]

  3. anonymous
    • 4 years ago
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    my friend said its 3-x or -x+3

  4. anonymous
    • 4 years ago
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    Answer: -x+3

  5. ash2326
    • 4 years ago
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    factor x^2-x-12 as (x-4)(x+3) x^2-8x+16 as (x-4)^2 \[ (x-3)(x+3)/(x)(x-5) * (-x)(x-5)/(x-4)(x+3) * (x-4)(x-4)/(x-4)\]

  6. ash2326
    • 4 years ago
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    we get when we remove the common terms from numerator and denominator \[(x-3)(-1)\] or \((3-x)\)

  7. anonymous
    • 4 years ago
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    your confusing the person.. -_-

  8. anonymous
    • 4 years ago
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    with different answers

  9. anonymous
    • 4 years ago
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    dead retrice-_-

  10. anonymous
    • 4 years ago
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    retrice

  11. anonymous
    • 4 years ago
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    lolol not to be mean

  12. anonymous
    • 4 years ago
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    sorry you're right

  13. anonymous
    • 4 years ago
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    my answer is right. - Nikki x <3 (:

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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