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anonymous

  • 5 years ago

Solve. \[7^{x-4} = 7 ^{4x+7}\]

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  1. myininaya
    • 5 years ago
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    just set the exponents equal and solve for x x-4=4x+7

  2. anonymous
    • 5 years ago
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    i get -11/3 and thats not one of the choices.

  3. myininaya
    • 5 years ago
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    Subtract x on both sides -4=3x+7 Subtract 7 on both sides -11=3x and divide by 3 on both sides -11/3=x I agree with you answer Is it perhaps written in decimal form or as a mix fraction?

  4. myininaya
    • 5 years ago
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    \[x=-\frac{3(3)+2}{3}=-(\frac{3(3)}{3}+\frac{2}{3})=-(3+\frac{2}{3})=-3\frac {2}{3}\]

  5. anonymous
    • 5 years ago
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    the answers are A: x = -4, B: x=2/3, C:x=-12/5, D: x=4

  6. myininaya
    • 5 years ago
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    The question is correct, right?

  7. anonymous
    • 5 years ago
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    it is \[-\frac{11}{3}\] for sure

  8. myininaya
    • 5 years ago
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    yep unless the problem is wrong

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