## anonymous 4 years ago For what value(s) of x is √(– x)^2 = –| x |? A. x ≤ 0 B. x = 0 only C. x ≥ 0 D. no values of x

1. anonymous

B.

Interesting...... my take is D.

But I am not sure. The right hand side -|x| will always be negative. The left hand side will be positive unless we are recognizing the negative root (which I am willing to do).

4. myininaya

$\sqrt{-(0)^2}=-|0| \text{ is true}$

5. myininaya

I agree with B

6. anonymous

Told you :)

Lets do a trial. Let x=-1, then $\sqrt{(-(-1))^{2}}=-|-x|$$\pm1=-1$ I guess this is not totally true. Forget d

but I can't forget it entirely lol

9. myininaya

radar is definitely works for x=0

10. myininaya

it*

Yes b is for sure, I was trying to eliminate a c and d.

12. myininaya

$\sqrt{(-x)^2}=|-x|$

I guess$\pm0=-|0|$ is definitely true.

14. myininaya

$|-x|=-x \text{ if x<0} ; |-x|=x \text{ if x>0}$ hey hershey calm down just because you are confident in you answer doesn't mean everyone is

Thanks all, I am convinced B is correct.

16. myininaya

good job though hershey

17. anonymous

:)

The other distractors (a, c, and d) truly distracted me lol

19. myininaya

Radar try writing them both as a piece wise function.

20. myininaya

Ok, lol

Yes I see it, the double negative when a x<0 was substituted on the left was confusing me.

The fact that the total was being squared, then the square root was to be taken. The right hand side was straight forward for me. Thank goodness, I have passed the test taking phase of my life lol.

23. myininaya

lol This is the way I looked at it $\sqrt{(-x)^2}=|-x|=|-1||x|=1|x|=|x|$

24. myininaya

$|x|=-|x| \text{ when x=0 only}$

Yes that makes it most obvious to the casual observer (like me)

26. myininaya

I was thinking about doing this a longer way, but this is the most easiest way

Yes that does simplify it.

28. anonymous

if you wouldn't mind i posted another question i need help with