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anonymous
 4 years ago
Help please :P
anonymous
 4 years ago
Help please :P

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Show geometrically why \[ \int\limits_{1}^{0}\sqrt{2x ^{2}}dx\] = (pi/4)+(1/2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry I am bad at writing equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You have to break the area under y=sqrt(2x^2) into two peices a circle and and a triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry a sector of a circle and a right triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327347617343:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup so. the first part is the sector of a circle (1/4)(area of the circle) + the second part which is the triangle from sqrt(2) to 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well we need the area only from 0 to 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ehhhhhhhhh............. hmm.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0area = pi * r^2 = pi(2) than divide by the angle/360 THAN add on the additional triangle :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that took some time OTL

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait jsut checking it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok drawing time :P 1 min

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that was a innovative problem. thanks :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0LOL Thanks that was a great drawing :DD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks, i'm so good at drawing :P
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