anonymous
  • anonymous
what is the simplest form of (4x^2-25)/(2x-5)
Mathematics
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
(4x^2-25)/(2x-5) ((2x-5)(2x+5))/(2x-5) 2x+5
anonymous
  • anonymous
im still confused . can you explain how you got this?like in words?
jim_thompson5910
  • jim_thompson5910
I factored 4x^2-25 to get (2x-5)(2x+5) using the difference of squares rule

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jim_thompson5910
  • jim_thompson5910
then i divided and canceled out the "2x-5" terms
jim_thompson5910
  • jim_thompson5910
to be left with 2x+5 as the answer
anonymous
  • anonymous
ok but the answers show more. can i show you my choices?
jim_thompson5910
  • jim_thompson5910
sure thing
anonymous
  • anonymous
2x – 5, with the restriction x ≠ – 5/2 2x + 5, with the restriction x ≠ 5/2 2x – 5, with the restriction x ≠ 5/2 2x + 5, with the restriction x ≠ – 5/2
jim_thompson5910
  • jim_thompson5910
well you can't divide by zero, so 2x-5 cannot be zero if it were, then 2x-5=0 2x = 5 x = 5/2 which means that x = 5/2 makes the denominator zero. So to avoid dividing by zero, we just add the restriction that x cannot be 5/2 So the answer is choice B
anonymous
  • anonymous
thank you
jim_thompson5910
  • jim_thompson5910
you're welcome

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