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anonymous

  • 5 years ago

what is the simplest form of (4x^2-25)/(2x-5)

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  1. jim_thompson5910
    • 5 years ago
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    (4x^2-25)/(2x-5) ((2x-5)(2x+5))/(2x-5) 2x+5

  2. anonymous
    • 5 years ago
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    im still confused . can you explain how you got this?like in words?

  3. jim_thompson5910
    • 5 years ago
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    I factored 4x^2-25 to get (2x-5)(2x+5) using the difference of squares rule

  4. jim_thompson5910
    • 5 years ago
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    then i divided and canceled out the "2x-5" terms

  5. jim_thompson5910
    • 5 years ago
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    to be left with 2x+5 as the answer

  6. anonymous
    • 5 years ago
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    ok but the answers show more. can i show you my choices?

  7. jim_thompson5910
    • 5 years ago
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    sure thing

  8. anonymous
    • 5 years ago
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    2x – 5, with the restriction x ≠ – 5/2 2x + 5, with the restriction x ≠ 5/2 2x – 5, with the restriction x ≠ 5/2 2x + 5, with the restriction x ≠ – 5/2

  9. jim_thompson5910
    • 5 years ago
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    well you can't divide by zero, so 2x-5 cannot be zero if it were, then 2x-5=0 2x = 5 x = 5/2 which means that x = 5/2 makes the denominator zero. So to avoid dividing by zero, we just add the restriction that x cannot be 5/2 So the answer is choice B

  10. anonymous
    • 5 years ago
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    thank you

  11. jim_thompson5910
    • 5 years ago
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    you're welcome

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